All categories

3 years ago

Complete the statements.

Mathematics

2 answers:

Fofino [41]3 years ago

7 0

Answer: Substitute the given value for the (variable)

Use the (order of operations) to simplify

First class complete (multiplication) inside the parentheses

Next, complete the (subtract) inside the parentheses

The value is (8)

Step-by-step explanation:

IRISSAK [1]3 years ago

6 0

Answer:

ax+b

Step-by-step explanation:

You might be interested in

Starting from the same place, Ryu walks due west and Samantha walks due east.

juin [17]

For Samantha, 2 tick marks east is 120 units east because 1 tick is 60 units.

For Ryu, 8 tick marks west is 480 units west because 1 tick is 60 units.

They are walking to form a line. Just add their distances from 0.

120 + 480 = 600.

--------------------------0----------------------------

Ryu: 480 Samantha: 120

480 + 120 = 600.

600 units, or feet.

5 0

3 years ago

14. Subtract: 5 - 3 1/3. A. 313 B.223 C. 12/3 D.23

exis [7]

Answer:

The answer is 1 $\frac{2}{3}$

The work is shown on the picture.

Step-by-step explanation: Hope this helps and mark brainliest if ya want :)!

6 0

3 years ago

SOLVE: 6^3x+2 = 4^x-5

Lilit [14]

There's an app called photomath that would be useful for these kinds of problems!

6 0

3 years ago

Prove the sum of two rational numbers is rational where a, b, c, and d are integers and b and d cannot be zero. Fill in the miss

mario62 [17]

Answer:

We conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

$\frac{ad+cb}{bd}$ ∵ b≠0, d≠0, so bd≠0

Step-by-step explanation:

Let a, b, c, and d are integers.

Let a/b and c/d are two rational numbers and b≠0, d≠0

Proving that the sum of two rational numbers is rational.

$\frac{a}{b}+\frac{c}{d}$

As the least common multiplier of b, d: bd

Adjusting fractions based on the LCM

$\frac{a}{b}+\frac{c}{d}=\frac{ad}{bd}+\frac{cb}{db}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{ad+cb}{bd}$

As b≠0, d≠0, so bd≠0

Therefore, we conclude that the sum of two rational numbers is rational.

Hence, the fraction will be a rational number. i.e.

$\frac{ad+cb}{bd}$ ∵ b≠0, d≠0, so bd≠0

3 0

3 years ago

According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating

Natali [406]

Answer:

a) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

$H_0: \mu=32.48\\\\H_a:\mu< 32.48$

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565$

The degrees of freedom for this sample size are:

$df=n-1=65-1=64$

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Critical value approach

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0

3 years ago