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Law Incorporation [45]
2 years ago
5

Algebra 2 please help quickly

Mathematics
1 answer:
BabaBlast [244]2 years ago
7 0

Answer:

c

Step-by-step explanation:

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How do you solve 8x+5=3x+15
sladkih [1.3K]
8x + 5 = 3x + 15

8x - 3x = 15 - 5   (put same kinds of number on one side and change the signs)

5x = 10 (simplify)

5x/5 = 10/5 (simplify)

x = 2 (answer)

hope this helps

8 0
3 years ago
On Wednesday, how many total kilograms of flour were prodľiced at plant #1 and
Svet_ta [14]

Answer:

110,000 kg

Step-by-step explanation:

Just look at the kilos of flour produced on Wednesday from both plants and add them together :)

8 0
3 years ago
Consider the geometric sequence below.
vladimir1956 [14]

Answer:

f(1) = 8

Common ratio: 0.5

Step-by-step explanation:

f(1) means the firs term in a sequence.

In the function f(n), represented by 8, 4, 2, 1, .., the first term is 8.

f(1) = 8

To find the common ratio, divide any term by the term before it.

We can use any two of the given terms in the sequence EXCEPT for 8 because it is the first term and does not have a term before it.

I choose to divide the second term by the first term:

4/8 = 1/2 = 0.5

3 0
3 years ago
2x + 3y = 17<br> 5x + 6y = 32<br><br> Usibg method if elimination
lions [1.4K]

Answer:

Solution (-2, 7)

Step-by-step explanation:

2x + 3y = 17      (1)

5x + 6y = 32    (2)

Using elimination method

Multiply (-2) to the equation (1)

-4x - 6y = -34  

Now you have 2 new equations

-4x - 6y = -34

5x + 6y = 32

----------------------------Add

x = -2

Substitute x = -2 into 2x + 3y = 17

2(-2) + 3y = 17

- 4 + 3y = 17

3y = 21

 y = 7

Solution (-2, 7)

6 0
2 years ago
Find the smallest multiple of 15 such that each digit of the multiple is either 0 or 4
SCORPION-xisa [38]
The answer is 4440.  You can determine this by using your rules of divisibility.  We know that is must end in a 0 or 5 to be divisible by 5 and that the sum of the digits must be divisible by 3 in order to divide by 3. One or two 4's together are not divisible by 3.  Three 4's are, but it must end in 0 to be divisible by 5 as well.


5 0
3 years ago
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