First, let's put the second equation, <span>x-2.23y+10.34=0, in terms of y:
x - 2.23y +10.34 = 0
2.23y = x + 10.34
y = .45x + 4.64
Now we can substitute the right side of this equation for y in the first equation
</span><span>y=2x^2+8x
.45x + 4.64 = 2x^2 + 8x
Turn it into a quadratic by getting 0 on one side:
2x^2 + 8x - .45x - 4.64 = 0
2x^2 + 7.55x - 4.64 = 0 Divide both sides by 2
x^2 + 3.76x - 2.32 = 0
x =( -b +/- </span>√(b² - 4ac) ) / 2a
x =( -3.76 +/- √(14.14 + 9.28)) ÷ 2
x = .54 or -4.31
Plug the x values into y = .45x + 4.64
y = .45 (.54) + 4.64
y = 4.88 when x= .54
y = .45 (-4.31) + 4.64
y = 2.70 when x= -4.31
Solution set:
{ (0.54, 4.88) , (-4.31, 2.70) }
2x + y = 8
3x - y = 17
---------------add
5x = 25
x = 25/5
x = 5
2x + y = 8
2(5) + y = 8
10 + y = 8
y = 8 - 10
y = -2
solution is (5,-2).....this is consistent and independent because it has one solution
4x + 2 = 62
4x = 62 - 2
4x = 60
x = 60/4
x = 15 <===
12y = 144
y = 144/12
y = 12 <===
alternate interior angles are congruent
Answer: x=3 y=3
Step-by-step explanation:
Assuming you meant 2x+3y=15 as the first problem. You have to make either both the x’s or both the y’all equal in both equations first. Multiply the second equation by 2 (for x’s) and you’ll get 2x+2y=12. The 2x cancels out so you’re left with 3y=15 and 2y=12. Subtract 2y=12 from 3y=15 and you get y=3.
Repeat to figure out x. Multiple second equation by 3 (for equal y’s) and you get 3x+3y=18. This time the first equation is being subtracted from the second one. (3x+3y=18) - (2x+3y=15). Y’s cancel out and you’re left with (3x=18)-(2x=15. Subtract and you get x=3
Answer:
D) 3
Step-by-step explanation:
22 * 2 = 44
To have a remainder 3, the number should be 44 + 3 = 47
47 ÷ 22 , leaves a remainder 3.
47 +22 = 69
69 ÷ 3 leaves a remainder 3.
69 +22 = 91
91 ÷ 3 leaves a remainder 3.
Answer: 47 , 69 , 91
