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Allushta [10]
3 years ago
10

supposea,b,and c represent three postive whole numbers. if a+b=19, b+c=28, and a+c=25 what are the values of a, b, and c? solve

for x sqaured 2 -4x +3 = 0
Mathematics
1 answer:
777dan777 [17]3 years ago
8 0
Hello can you help me Solve each system of equations by GRAPHING. Clearly identify your solution.
(4x-y=3)
(3x+y=4)


Please help I need this answer and an explanation of how you got it I really do need this if you can help please it would mean so much to me I REALLY NEED HELPPPP
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What is the sum of 5.89732 304.615
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310.51232

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2 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
During a period of 45 days, Delynn played soccer on 3/5 of the days. On how many days did she play soccer?
Archy [21]

Answer:

Step-by-step explanation:

No. of days Delynn played soccer = 3/5 of 45

              = (3/5) * 45   = 3*45/5 = 3*9

              = 27 days

8 0
3 years ago
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