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adelina 88 [10]
2 years ago
9

Plz i will give u 93 point and a brainlylist and I will add u as a friend

Mathematics
2 answers:
kotegsom [21]2 years ago
7 0

Answer:

cover half with houses

Step-by-step explanation:

pls Mark me as brainlyest

sveticcg [70]2 years ago
3 0

Answer:

here ya go, answer in the image

Step-by-step explanation:

48/100

thx for brainly <3

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EastWind [94]

Answer:

x = 4

Step-by-step explanation:

all angles in triangle add to 180

90+70=160

180-160=20

20÷5=4

6 0
3 years ago
the area of a rectangular ice skating ink is 900 square yards. If the length of the ring is 100 yards. What is within of the rin
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Length x Width = Area
In your case, you'd want to flip around the equation.
100+x=900
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(4xy+6y-4x)-5xy-4x+3y STEP explanation pls​
kari74 [83]

Answer:

this is the solution

<h3>please follow me and mark it brainliest</h3>

8 0
3 years ago
Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression
VMariaS [17]
To find the answer to this, you have multiply both expressions by each other. To do this, you have to multiply each term in the first expression by each term in the second expressions. This yields the following: 3x^4-9x^3-3x^2+5x^3-15x^2-5x+10x^2-30x-10. Combing like terms and simplifying gives the final expression: 3x^4 - 4x^3 - 8x^2 - 35x - 10
3 0
3 years ago
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Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
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