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3 years ago

The sum of a number and 3 is 6 less than twice that number. Solve

Mathematics

1 answer:

pshichka [43]3 years ago

6 0

Answer:

there are two operation end modes [ = , < ]

so, it remains an expression

Step-by-step explanation:

let the number be x :

$\{(n + 3) = 6 \} < 2n$

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Which two values of x are roots of the polynomial below?

Julli [10]

Answer:

B. and C.

Step-by-step explanation:

1. Set the polynomial equal to zero:

x² + 5x + 7 = 0

2. Plug the given values of a, b, and c into the quadratic formula:

$x=\frac{-5+-\sqrt{5^{2}-4(1)(7) } }{2(1)}$

3. Solve the square root:

$x=\frac{-5+-\sqrt{25-4(1)(7)} }{2(1)}$

$x=\frac{-5+-\sqrt{25-28} }{2(1)}$

$x=\frac{-5+-\sqrt{-3} }{2(1)}$

4. Simplify the rest:

$x=\frac{-5+-\sqrt{-3} }{2}$

5. Separate the solutions:

$x=\frac{-5+\sqrt{-3} }{2} , x=\frac{-5-\sqrt{-3} }{2}$

Thus, options B and C are the answers.

hope this helps!

4 0

3 years ago

Show all work. What are the zeros of the function?<br> f(x) = 2x^2 − 8x − 10

vivado [14]

(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5

S = {-1;5}

3 0

3 years ago

What is the range of the function? f(x) = -2^x + 1

Readme [11.4K]

{y|1 > y}, (-∞, 1); you did not specifically mention what notation you needed, so I wrote both [Internal Notation and Set Notation].

6 0

3 years ago

Read 2 more answers

In triangle JKL, tan(bº) =

VikaD [51]

This is the working outs

8 0

3 years ago

What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L container at 25.0°C?

drek231 [11]

Answer:

1.2218 atm

Step-by-step explanation:

From ideal gas formula,

PV=nRT

Where n= number of moles

V= volume

T= temperature=25.0°C

= (273 + 25) = 298 K

R= gas constant = 0.082 l atm /K mol.

Making P subject of formula we have

P= [nRT] /V

Then substitute the values we have

P= [0.5 x 0.082 x 298] / 10

P= 1.2218 atm

6 0

3 years ago