Please what is the answer fast very

What is the prime factorization of 24? 1. 2x2x2x3 2. 2x2x3 3. 8x3 4. 6x4

nika2105 [10]

Answer:

1. 2x2x2x3

Step-by-step explanation:

Let's do process of elimination.

2. 2x2x3

2x2=4 4x3=12

2 is false.

3. 8x3

8x3=24

3 is true, but 8 is not a prime number.

4. 6x4

6x4=24

4 is true, but 6 is not a prime number.

This leaves 1. 2x2x2x3.

1. 2x2x2x3

2x2=4 2x3=6 6x4=24

1 is true, and 2 and 3 are prime numbers. So, the answer is 1.

-hope it helps

6 0

3 years ago

Read 2 more answers

A bag contains 6 red marbles and 24 green marbles.If a representative sample contains 2 red marbles, then how many green marbles

Rainbow [258]

Answer:

8

Step-by-step explanation:

6 0

3 years ago

(x − 3)(2x2 − 5x + 1)

Ira Lisetskai [31]

Answer:

2x3 − 11x2 + 16x − 3

Step-by-step explanation:

7 0

3 years ago

Solve if x is 3. 91+x raise to power2

Triss [41]

X=3
91 + x^2
91 + 3^2
91 + 9
91 + 9 = 100

6 0

4 years ago

Read 2 more answers

Solve the given system of equations using either Gaussian or Gauss-Jordan elimination. (If there is no solution, enter NO SOLUTI

cricket20 [7]

Answer:

The system has infinitely many solutions

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

Step-by-step explanation:

Gauss–Jordan elimination is a method of solving a linear system of equations. This is done by transforming the system's augmented matrix into reduced row-echelon form by means of row operations.

An Augmented matrix, each row represents one equation in the system and each column represents a variable or the constant terms.

There are three elementary matrix row operations:

Switch any two rows
Multiply a row by a nonzero constant
Add one row to another

To solve the following system

$\begin{array}{ccccc}x_1&-3x_2&-2x_3&=&0\\-x_1&2x_2&x_3&=&0\\2x_1&+3x_2&+5x_3&=&0\end{array}$

Step 1: Transform the augmented matrix to the reduced row echelon form

$\left[ \begin{array}{cccc} 1 & -3 & -2 & 0 \\\\ -1 & 2 & 1 & 0 \\\\ 2 & 3 & 5 & 0 \end{array} \right]$

This matrix can be transformed by a sequence of elementary row operations

Row Operation 1: add 1 times the 1st row to the 2nd row

Row Operation 2: add -2 times the 1st row to the 3rd row

Row Operation 3: multiply the 2nd row by -1

Row Operation 4: add -9 times the 2nd row to the 3rd row

Row Operation 5: add 3 times the 2nd row to the 1st row

to the matrix

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

The reduced row echelon form of the augmented matrix is

$\left[ \begin{array}{cccc} 1 & 0 & 1 & 0 \\\\ 0 & 1 & 1 & 0 \\\\ 0 & 0 & 0 & 0 \end{array} \right]$

which corresponds to the system

$\begin{array}{ccccc}x_1&&-x_3&=&0\\&x_2&+x_3&=&0\\&&0&=&0\end{array}$

The system has infinitely many solutions.

$\begin{array}{ccc}x_1&=&-x_3\\x_2&=&-x_3\\x_3&=&arbitrary\end{array}$

7 0

3 years ago