1.09÷3= .3633 each
4.49÷12= .37416 each
8.78÷24= .3658 each
so the first one
Answer:
15
Step-by-step explanation:
a^2 + b^2 = c^2
20^2 +b^2 = 25^2
400 + b^2 = 625
-400 -400
b^2 = 225
b = √225
b = 15
Answer:259
Step-by-step explanation:
Its summation of 6^i-1 for values of I = 1,2,3 and 4
= 6^0 + 6^1 +6^2 +6^3
=259
Using the normal distribution, it is found that 0.26% of the items will either weigh less than 87 grams or more than 93 grams.
In a <em>normal distribution</em> with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem:
- The mean is of 90 grams, hence .
- The standard deviation is of 1 gram, hence .
We want to find the probability of an item <u>differing more than 3 grams from the mean</u>, hence:
The probability is P(|Z| > 3), which is 2 multiplied by the p-value of Z = -3.
- Looking at the z-table, Z = -3 has a p-value of 0.0013.
2 x 0.0013 = 0.0026
0.0026 x 100% = 0.26%
0.26% of the items will either weigh less than 87 grams or more than 93 grams.
For more on the normal distribution, you can check brainly.com/question/24663213