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3 years ago

How can I use context clues and keywords to translate situations into inequalities? Explain with an example of your own.

1 answer:

3 0

Consider the following example:

Mira and Lola are looking to hire a hall for their 18th birthday party. They are expecting at least 50 guests and want a hire that will accommodate the party. Write this requirement as an inequality

Solution: the keyword here is 'at least' because it means that the hall must be able to accommodate a minimum of 50 people. It is a clue that Mira and Lola are expecting more than 50 guests. The inequality symbol for this context is 'more than or equal to' and as inequality, we have x ≥ 50

You might be interested in

How do you convert the decimal 0.24 to fraction in the simplest form

RideAnS [48]

Answer:

0.24---> 24/100 ---> 6/25

Step-by-step explanation:

hope that helps

6 0

1 year ago

A 20-person fraternity is making their weekend plans around 5 different parties in IV. Each brother will attend exactly one of t

skad [1K]

Answer:

3876

Step-by-step explanation:

Given the following :

Fraternity members = 20

They are to attend 5 different parties in groups of 4

Meaning a group = 4 persons

Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).

Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.

Group members are in 4's

19C4

From: nCr = n! /(n-r)! r!

19C4 = 19! / (19 - 4)! 4!

= 19! / 15! 4!

= (19 * 18 * 17 * 16) / (4 * 3 * 2)

= 93024 / 24

= 3876

3 0

4 years ago

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>