All categories

3 years ago

Find the range of the data set

Mathematics

2 answers:

-Dominant- [34]3 years ago

8 0

Answer:

Step-by-step explanation:

range=highest value -lowest value

Therefore, 54-29=24

ladessa [460]3 years ago

7 0

Answer:

Step-by-step explanation:

54-26=28.

You might be interested in

NO LINKS, WILL GIVE BRAINLIEST

KATRIN_1 [288]

For the Bots:

NO LINKS

Question:

What is the area of the

rectangle?

(rectangle is 5/7 ft wide and 3 1/2 ft long)

Enter your answer as a mixed number in simplest form in the box.

Answer:

2 1/5

Step-by-step explanation:

Because we are finding the area we are multiplying and the formal is L x W = Area so the Length is 3 1/2 and the width is 5/7 so we multiply them and we get: 2.5

3 1/2 x 5/7 = 2.5 let make it a mixed number 5/2 let simplify it now 5 divided by 2 = 2 1/5

is the answer

5 0

3 years ago

70 POINTS! ∆ABC is reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the li

madam [21]

Answer:

A'(1, 1); B'(3, 2); C'(1, 2)

Step-by-step explanation:

The original points are A(1,1 ), B(2, 3) and C(2, 1).

Reflecting the triangle across the x-axis will negate every y-coordinate; this maps

(1, 1)→(1, -1); (2, 3)→(2, -3); (2, 1)→(2, -1)

Rotating the figure 90° clockwise about the origin switches the x- and y-coordinates and negates the x-coordinate; this maps

(1, -1)→(-1 -1); (2, -3)→(-3, -2); (2, -1)→(-1, -2)

Reflecting across the line y=x will negate both the x- and y-coordinates; this maps

(-1, -1)→(1, 1); (-3, -2)→(3, 2); (-1, -2)→(1, 2)

3 0

3 years ago

Read 2 more answers

I NEED HELP RN PLEASEEEE ITS AN EMERGENCY!!

strojnjashka [21]

Answer:

The answer is C) $12\sqrt{2}$ .

Step-by-step explanation:

For a real number $a$ ,

$\sqrt{a} \cdot \sqrt{a} = a$ .

In other words, multiplying a square root by itself gets rid of the square root.

How does this rule apply here?

$24 = 2\times 12$ .

Similarly,

$\sqrt{24} = \sqrt{2}\times \sqrt{12}$ .

That is:

$\begin{aligned}\sqrt{24}\times \sqrt{12} &= (\sqrt{2}\times \sqrt{12}) \times \sqrt{12}\\&=\sqrt{2}\times (\sqrt{12}\times \sqrt{12}) && \begin{array}{l}\text{By the associative property}\\\text{of multiplication}\end{array}\\&=\sqrt{2} \times 12\\ &= 12\sqrt{2}\end{aligned}$ .