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Volgvan
3 years ago
7

Pls one questionn onlyy plssssss

Mathematics
1 answer:
tatuchka [14]3 years ago
8 0
A)trapez or parallelogram
b)yes they are collinear because they are on the same segment
c)yes

I hope I helped you =)
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Show that the equation x^3+7x-4=0 has a solution between x=0 and x=1
Aleksandr [31]

Step-by-step explanation:

Using the Intermediate Value Theorem, the following is applied:

"If f(x) is a continuous on interval [a,b] and we have two points f(a) and f(b) then there must be some value c such that f(a)<f(c)<f(b).

So here there must be a c such that

f(0) < f(c) < f(1)

Note: F(c)=0, the questions that the function have a solution between 0 and 1, so that means we must have some value, c such that f(c)=0 that exists

Next, plug in the x values into the function

f(0)  =  - 4

f(1) =  {1}^{3}  + 7(1) - 4 = 4

Since cubic functions are continuous and -4<0<4, then there is a solution c that lies between f(0) and f(1)

3 0
2 years ago
Liz needs to keep no less than $500 in her checking account to avoid fees. she had $524.75 before writing a check for $65.99. ho
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If she needs to keep $500 in her account and she just wrote a check for $65.99 she needs to deposit $41.24 to be at $500 when the $65.99 is withdrawn.
8 0
4 years ago
Repeat from other question
mihalych1998 [28]

Answer:

P(-1) = -18

Step-by-step explanation:

P(x) = x^4 +5x^3 -4x-18

p(-1) = (-1)^4 + 5(-1) -4(-1) -18

P(-1) = 1 -5 +4 -18

      = -4+4-18

      = -18

3 0
3 years ago
Read 2 more answers
Mark the Brainleist! What is the square root of 35? Explain
Softa [21]

Answer:

The square root of 35 is 5.92. I might be wrong

6 0
3 years ago
Match the sets of points representing one-to-one functions with the sets of points representing their inverse functions. h = {(1
geniusboy [140]
The one-to-one functions given as sets of points and their possible inverse functions are given as
h   = { (1,1),  (2,2), (3,3),   (4,4),  (5,5),  (6,6)}
g   = { (1,3), (2,6), (3,9), (4,12), (5,15),  (6,18)}
f    = { (1,2), (2,3), (3,4),  (4,5),  (5,6),  (6,7)}
i    = { (1,1),  (2,3), (3,5),  (4,7),  (5,9),  (6,11)} 

h⁻¹ = { (1,1),  (2,2), (3,3),  (4,4),  (5,5),  (6,6)}
i⁻¹  = { (1,1),  (3,2), (5,3),  (7,4),  (9,5),  (11,6)}
g⁻¹ = {(3,1), (6,2), (9,3), (12,4), (15,5), (18,6)}
f⁻¹  = {(2,1), (3,2), (4,3),  (5,4),  (6,5),  (7,6)}

The inverse function of a given function should have the coordinates reversed. 
Therefore the matches between the given functions and their inverse functions are given in the table below.

function Inverse function
-----------  ------------------------
        h            h⁻¹
        g            g⁻¹
        f             f⁻¹
        i             i⁻¹

Answer:
The given functions and their corresponding inverses are correct.
7 0
4 years ago
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