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Inessa05 [86]
3 years ago
5

What is the value of x? [2(+10)] (3x-30)

Mathematics
2 answers:
Elodia [21]3 years ago
7 0

Answer:

x=10

Step-by-step explanation:

Given:

[2(+10)] (3x-30)=0

For the given equation, equating to zero for standard form equation to find 'x'

                    [2(+10)] (3x-30)=0

                          (20)(3x-30)=0\\60x-600=0\\60x=600\\x=600/60\\x=10

On solving the equation the value of x is 10

irina1246 [14]3 years ago
6 0

Answer:

x = 10

Step-by-step explanation:

[2(+10)] (3x-30)

Solve :

[2(+10)] (3x-30)

[20] (3x-30) = 0

60x - 600 = 0

60x = 600

x = 600/60

x = 10

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Marissa claims that stacking 6 blocks with dimensions of One-half times 1 times 1 will give the same volume as stacking 9 blocks
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Answer:

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  • (D)Three of the one-third cubes will make 1 unit cube.
  • (E)Two of the one-half cubes will make 1 unit cube.
  • (F)Both stacks will have a volume of 3 cubic units.

Step-by-step explanation:

Marissa claims that stacking 6 blocks with dimensions of \frac{1}{2}X1X1  will give the same volume as stacking 9 blocks with dimensions of \frac{1}{3}X1X1  .

First, let us examine the volume of each of the blocks.

<u>For Block 1</u>

The dimensions are:   \frac{1}{2}X1X1

Volume of 1 block =  \frac{1}{2}X1X1= \frac{1}{2} $ cubic units

Volume of 6 blocks of dimension   =6* \frac{1}{2} =3$ cubic units

<u>For Block 2 </u>

The dimensions are:   \frac{1}{3}X1X1

Volume of 1 block =  \frac{1}{3}X1X1=\frac{1}{3} $ cubic units

Volume of 9 blocks of dimension =9*\frac{1}{3} =3$ cubic units  

The following statements out of Marissa's claim are true:

(A)Six of the one-half cubes would have a volume of 3 cubic units.

(D)Three of the one-third cubes will make 1 unit cube.

 3*\frac{1}{3} =1$ cubic units

(E)Two of the one-half cubes will make 1 unit cube.

 2*\frac{1}{2} =1$ cubic units

(F)Both stacks will have a volume of 3 cubic units.

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3 years ago
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BabaBlast [244]

Answer:

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There are three people. They have $6.90. You divide 6.9 by 3 and you get 2.3. You don't move the decimal place.

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