2 years ago

Please help. Don’t answer if you don’t know the answer. Your waisting my points and answer spaces when you do so. Thanks-

Mathematics

1 answer:

ELEN [110]2 years ago

4 0

Answer:

huh? I can understand where. is answer

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Write and equation for the line that has a slope of one half and passes through the point 2,4

jekas [21]

The equation in slope intercept form is

Y=.5x+3

8 0

3 years ago

Please solve with working out simultaneous equations 3x+2y=12 2x+2y=10

Novay_Z [31]

Here, 3x + 2y = 12
2x + 2y = 10

Subtract 2nd from 1st equation,
x = 2

Now, substitute in 2nd,
2(2) + 2y = 10
2y = 10 - 4
y = 6/2
y = 3

In short, Your Answer would be: (2, 3)

Hope this helps!

4 0

3 years ago

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Find the gradient of the line segment between the points N(-1,2) and M(-6,3)

siniylev [52]

Answer:

1/5

Step-by-step explanation:

Gradient is another word for slope. To find the gradient, we have to use a formula.

8 0

3 years ago

Please solve for all three parts of the question.

neonofarm [45]

Answer:

f(-5) = 25

f(0) = -2

f(5) = 16

Step-by-step explanation:

Given the functions;

To get f(-5), we will use the function of x where x is less than 0 since -5 is less than zero

at where x < 0, f(x) = x^2

f(-5) = (-5)^2

f(-5) = 25

b) For f(0), where the point where x = 0, f(x)= -2

Hence the value of f(o) = -2

c) For f(5), the function where x > 5 is f(x) = 2x+6

f(x) = 2x+6

f(5) = 2(5)+6

f(5) = 16

5 0

2 years ago

Solve the equation. x2 18x 81 = 25 a. 14, 4 b. –4, –14 c. 14, –14 d. –4, 4

Snowcat [4.5K]

Answer:

The answer is the option B

$-4,-14$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}+18x+81=25$

$x^{2}+18x+56=0$

$a=1\\b=18\\c=56$

substitute in the formula

$x=\frac{-18(+/-)\sqrt{18^{2}-4(1)(56)}} {2(1)}$

$x=\frac{-18(+/-)\sqrt{100}} {2}$

$x=\frac{-18(+/-)10} {2}$

$x1=\frac{-18+10} {2}=-4$

$x2=\frac{-18-10} {2}=-14$

7 0

3 years ago

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