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SIZIF [17.4K]
2 years ago
15

When multiplying decimals, how do you find the number of

Mathematics
1 answer:
lys-0071 [83]2 years ago
7 0
Count the numbers right to the decimal point and then count that much of numbers from right to left and apply it

Ex - 2.50
*. 2.50

——————
6.2500. There are 4 numbers right to the decimal point
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Brainliest if correct
natali 33 [55]

\left(15^{1/5} \right)^5  = 15^{(5/5)} = 15^1 = 15

6 0
2 years ago
Complete the multiplication problem to find the answer.
melisa1 [442]

Answer: 88.74

Step-by-step explanation:

3 0
3 years ago
What is the answer to this problem?
Sergeu [11.5K]

Answer:

c

Step-by-step explanation:

6 0
3 years ago
Solve one of the following two non-homogeneous differential equations using whatever technique your prefer. Put an "X" through t
noname [10]

Answer:

a.y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

by(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

Step-by-step explanation:

1.y''-4y'+4y=6x e^{2x}

Auxillary equation

D^2-4D+ 4=0

(D-2)(D-2)=0

D=2,2

Then complementary solution =C_1e^{2x}+C_2xe^{2x}

Particular solution =\frac{6 xe^{2x}}{(D-2)^2}

D is replace by D+2 then we get

P.I=\frac{6xe^{2x}}{0}

P.I=\frac{e^{ax}}{D+a} \cdot .V

where V is a function of x

P.I=\frac}x^3e^{2x}

By integrating two times

Hence, the general solution

y(x)=c_1e^{2x}+c-2xe^{2x}+x^3e^{2x}

b.y''+9y=5 cos x-7 sin x

Auxillary equation

D^2+9=0

D=\pm 3i

C.F=c_1 cos 3x+ c_2sin 3x

P.I=\frac{5 cos x-7 sin x}{D^2+9}

P.I=\frac{sin ax}{D^2+bD +C}

Then  D square is replace by -a square

D^2 is replace by - then we get

P.I=-5 cos x+7 sin x

The general solution

y(x)=c_1cos 3x+c_2 sin 3x-5 cos x+ 7sin x

4 0
3 years ago
Math question help me
vodka [1.7K]

may I ask if these questions' answer are always 2... or they can be other numbers too

8 0
2 years ago
Read 2 more answers
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