If $10,000 is invested at 6% annual interest compounded yearly, what is the account balance after 4 years, assuming no additiona
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In the first 10 -> 10 - 9 = 1 (contain a 3).
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n -> 10^n - 9^n (contain a 3).
<u>The answer is 3.439 numbers contain a 3 in the first 10.000</u>
In the first 100 -> 100 - 9 * 9 = 19 (contain a 3).
In the first 10^n -> 10^n - 9^n (contain a 3).
<u>The answer is 3.439 numbers contain a 3 in the first 10.000</u>