<img src="https://tex.z-dn.net/?f=3%5Cfrac%7B3%7D%7B4%7D%20%2B8%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1" title="3\frac{3}{4} +8\fr

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REY [17]

3 years ago

ac{3}{4}" alt="3\frac{3}{4} +8\frac{3}{4}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Dvinal [7]3 years ago

8 0

Ok done. Thank to me:>

ki77a [65]3 years ago

7 0

15/4+35/4
25/2
12 1/2
Hope this helped

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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The

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<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

${\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}$

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

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(4x-34)°

According to sum theory

${\boxed{\sf The \:sum\:of\:angles=180°}}$

Substitute the values

$\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180$

Remove brackets

$\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180$

Together like polynomials and constants

$\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180$

$\qquad \quad{:}\longmapsto\tt 11x-7=180$

Interchange sides

$\qquad \quad{:}\longmapsto\tt 11x=180+7$

$\qquad \quad{:}\longmapsto\tt 11x=187$

$\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}$

Simplify

$\qquad \quad{:}\longmapsto\tt x=17$

$\therefore\sf The \:value\:of\:x\;is\:17.$

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