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Sergio039 [100]
3 years ago
13

HELP ME PLEASE WALLAHI THIS SO HARDDDDDD

Mathematics
2 answers:
Andreas93 [3]3 years ago
5 0

Answer:

OK SO I AM NOT SURE BUT I THINK THIS IS THE ANSWER!

ok so think u have to do 6 x 5= 30 and then do 30 divided by 3 which is 10. so think your answer is 10. again, i am not completely sure but I hope this helped!! <3  

(if this was correct please give brainliest!!)

frozen [14]3 years ago
3 0

Answer:

7.8

Step-by-step explanation:

Use the Pythagorean Theorem:

a² + b² = c²

Substitute sides in:

6² + 5² = c²

Solve:

6² + 5² = c²

36 + 25 = c²

61 = c²

c = √61

c = 7.8

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Which statement describes the end behavior of the function f(x)=3|X-7|-7
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Answer:

Step-by-step explanation:

absolute value is always positive

or

|x-3|≥0

f(x)≥-7

f(x) is open above.

it starts from above x-axis on the left and ends above x -axis.

7 0
4 years ago
Which fraction is equivalent to 3/18?
Flauer [41]
3/18=1/6
9/27=1/3
no one of these fractions is equivalent to 3/18
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%202x%20%3D%200" id="TexFormula1" title=" {x}^{2} + 2x = 0" alt=
Alex

Answer:

\textbf{Hello!}

\Longrightarrow2^2+2z=0

\Longrightarrow x_{1,\:2}=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:0}}{2\cdot \:1}

\Longrightarrow \sqrt{2^2-4\cdot \:1\cdot \:0}

\Longrightarrow =\sqrt{2^2-0}

\Longrightarrow =\sqrt{2^2}

\Longrightarrow=2

\Longrightarrow x_{1,\:2}=\frac{-2\pm \:2}{2\cdot \:1}

\Longrightarrow x_1=\frac{-2+2}{2\cdot \:1},\:x_2=\frac{-2-2}{2\cdot \:1}

\Longrightarrow\frac{-2+2}{2\cdot \:1}

\Longrightarrow =\frac{0}{2\cdot \:1}

\Longrightarrow =\frac{0}{2}

=0

\Longrightarrow\frac{-2-2}{2\cdot \:1}

\Longrightarrow =\frac{-4}{2\cdot \:1}

\Longrightarrow =\frac{-4}{2}

\Longrightarrow =-\frac{4}{2}

=-2

x=0,\:x=-2\Longleftarrow

\underline{HOPE ~IT~HELPS}

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4 years ago
In ∆STU, the measure of
lorasvet [3.4K]

Trigonometric Ratios

A right triangle is defined as a triangle that has one interior angle with a measure of 90°.

The trigonometric ratios are defined as relationships between sides and angles on right triangles.

To better explain the required ratio, we'll include the following image that contains the given triangle, as described in the question:

The cosine of the angle T (shown in the figure) is defined as:

\displaystyle\cos T=\frac{\text{adjacent side}}{\text{hypotenuse}}

The secant of an angle is the reciprocal of the cosine, thus:

\sec T=\frac{hypotenuse}{\text{adjacent side}}

The adjacent side to angle T is 77 and the hypotenuse is 85, thus:

\sec T=\frac{85}{77}

4 0
2 years ago
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