Answer:
The multiring aromatic hydrocarbons in the coal liquid were hydrogenated to give saturated molecules that contained only one aromatic ring. Of the several organic bases investigated, potassium bis(trimethylsilyl)amide was found to be the most effective catalyst.
Explanation:
A car traveling at
20 m/s starts to decelerate steadily it comes to a complete stop in 10s. The
equation for the acceleration is velocity divided by time. So divide 20 m/s by
10 s and you will get an acceleration of 2 m/s2.
Explanation:
Normally, fusion involves two heavy hydrogen nuclides but since we have 4 light hydrogen nuclides, two of which underwent positron emission, thus changing two protons into neutrons plus 2 positrons and 2 neutrinos. The resulting nucleus from this fusion reaction is an He-4 nucleus.
The balanced equation is,
OBz-(aq) + H2O(l) ---> HOBz(aq) + OH-(aq)
The equation for Kb is :
Kb = [HOBz][OH-]/[OBz]
<h3>What do we know about benzoate ion?</h3>
The conjugate base of benzoic acid, benzoate is the simplest member of the family of benzoates. It consists of a benzoic acid core with a proton missing to give it a charge of -1. It serves as a xenobiotic metabolite for humans as well as a metabolite for plants. It is a benzoic acid's conjugate base.
To learn more about pKb:
brainly.com/question/12193534
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Answer:
38 canisters
Explanation:
The combustion of propane can be represented by the equation below:
C₃H₈ (g) + O₂ (g) → CO₂ (g) + H₂O(g) ΔHc = -103.85 kJ/mol
The boiling of water is represented below:
H₂O(l) → H₂O(g) ΔH = Q = mcΔT
The heat necessary to make water reach the boiling point is Q, which is calculated with the mass of water (m = 4.0 kg), its specif heat capacity ( c = 4.200 J/kg°C) and temperature variation (ΔT = 100 - 25)
Therefore, ΔH = Q = 4.0 kg x 4.200 kJ/kg°C x 75 °C
ΔH = Q = 1260.0 kJ
This is the amount of heat necessary to heat the water every day. Since the expedition will last 7 days, the total heat will be 8820 kJ
Now we need to calculate the amount of propane needed to generate this heat:
1 mol C₃H₈ _______ 103.85 kJ
X _______ 8820 kJ
x = 84.9 mol C₃H₈
1 mol C₃H₈ _____ 44 g
84.9 mol C₃H₈ ___ x
x = 3735.6 g
1 canister _____ 100 g C₃H₈
x _____ 3735.6 g
x = 37.3 canisters
The minimum number of fuel canisters I must bring is 38 canisters.
