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madam [21]
4 years ago
8

A potassium bromide solution is 7.55% potassium bromide by mass and its density is 1.03 g/ml. part a what mass of potassium brom

ide is contained in 35.8 ml of the solution?
Chemistry
2 answers:
Alex73 [517]4 years ago
8 0

Answer : The mass of potassium bromide contained in 35.8 ml of solution is, 2.784 grams.

Explanation : Given,

Density of solution = 1.03 g/mole

7.55 % potassium bromide by mass means that 7.55 gram of potassium bromide present in 100 grams of solution. So,

Mass of potassium bromide = 7.55 g

Mass of solution = 100 g

First we  have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.03g/mole}=97.08ml

Now we have to calculate the mass of potassium bromide in 35.8 ml of the solution.

As, 97.08 ml of solution present in 7.55 gram of potassium bromide

So, 35.8 ml of solution present in \frac{7.55}{97.08}\times 35.8=2.784 gram of potassium bromide

Therefore, the mass of potassium bromide contained in 35.8 ml of solution is, 2.784 grams.

dezoksy [38]4 years ago
5 0
67.234 percent is correct
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WARRIOR [948]

Answer:

The answer to the question above is

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C = 29.36 kJ

Explanation:

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ΔHfus = 7.27 kJ/mol

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Tmelting = -95.0°C.

Initial temperature = -154.0°C

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Molar mass of acetone = 58.08 g/mol

Solution

Heat required to raise the temperature of solid acetone from -154 °C to -95 °C or 59 °C is given by

H = mCsolT = 87.1 g* 1.65 J/g°C* 59 °C = 8479.185 J

Heat required to melt the acetone at -95 °C = ΔHfus*number of moles =

But number of moles = mass÷(molar mass) = 87.1÷58.08 = 1.5

Heat required to melt the acetone at -95 °C =1.5 moles*7.27 kJ/mol = 10.905 kJ

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Total heat = 9971.21 J + 10.905 kJ + 8479.185 J = 29355.393 J = 29.36 kJ

The energy required to heat 87.1 g acetone from a solid at -154.0°C to a liquid at -42.0°C is 29.36 kJ

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Explanation:

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