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Andre45 [30]
2 years ago
8

Find the value of x. Only type the "number."

Mathematics
1 answer:
ASHA 777 [7]2 years ago
3 0

Answer:find the area i gaurntee once you do that you will start to get the problem

Step-by-step explanation:

You might be interested in
Use graph to answer question
slamgirl [31]

Answer:

cos(θ) = 3/5

Step-by-step explanation:

We can think of this situation as a triangle rectangle (you can see it in the image below).

Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.

Here we want to find cos(θ).

You should remember:

cos(θ) = (adjacent cathetus)/(hypotenuse)

We already know that the adjacent cathetus is equal to 3.

And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:

3^2 + 4^2 = H^2

We can solve this for H, to get:

H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5

The hypotenuse is 5 units long.

Then we have:

cos(θ) = (adjacent cathetus)/(hypotenuse)

cos(θ) = 3/5

5 0
3 years ago
Please help me solve question 1.
Andru [333]

Answer:

630

Step-by-step explanation:

4 0
3 years ago
Can someone please help me
viktelen [127]
The surface area Is 98
8 0
3 years ago
Find the limit of the function by using direct substitution. limit as x approaches four of quantity x squared plus three x minus
Yuliya22 [10]
\lim_{x \to 4} f(x)=x^2+3x-1
just subsitute
f(4)=4²+3(4)-1
f(4)=16+12-1
f(4)=28-1
f(4)=27

it approaches 27 as x approaches 4
5 0
3 years ago
Read 2 more answers
A piece of wire 13 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
Rom4ik [11]

The function you seek to minimize is

()=3‾√4(3)2+(13−4)2

f

(

x

)

=

3

4

(

x

3

)

2

+

(

13

−

x

4

)

2

Then

′()=3‾√18−13−8=(3‾√18+18)−138

f

′

(

x

)

=

3

x

18

−

13

−

x

8

=

(

3

18

+

1

8

)

x

−

13

8

Note that ″()>0

f

″

(

x

)

>

0

so that the critical point at ′()=0

f

′

(

x

)

=

0

will be a minimum. The critical point is at

=1179+43‾√≈7.345m

x

=

117

9

+

4

3

≈

7.345

m

So that the amount used for the square will be 13−

13

−

x

, or

13−=524+33‾√≈5.655m

5 0
3 years ago
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