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Katyanochek1 [597]
2 years ago
9

HELP IM STRUGGLING REAL BAD WITH THSI

Mathematics
2 answers:
saveliy_v [14]2 years ago
4 0

Answer:

GI = 72

Step-by-step explanation:

GI=48+HI

\frac{48}{HI} =\frac{30}{15}

HI=\frac{(48)(15)}{30} =\frac{720}{30} =24

Then:

GI=48+24=72

Hope this helps

ella [17]2 years ago
3 0
X = 24 (I used a ratio because it has to be adjacent.)
(WORK SHOWN BELOW)

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zimovet [89]

x=2+½*\sqrt{10}

or

x=2-½*\sqrt{10}

Answer:

Solution given:

y=2x²-5x+6.....[1]

y=3x+3.........….[2]

solving equation 1&2

2x²-5x+6=3x+3

2x²-5x-3x+6-3=0

2x²-8x+3=0

comparing above equation with ax²+bx+c=0 we get

a=2

b=-8

c=3

by using quadratic equation

x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}

x=\frac{+8±2\sqrt{10}}{4}

taking positive

x=\frac{+8+2\sqrt{10}}{4}

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taking negative

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3 years ago
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Damm [24]

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

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Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

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Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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Answer:

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Step-by-step explanation:

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