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skad [1K]
3 years ago
7

Identify the stages where gravity causes water to move downward.

Biology
2 answers:
Yakvenalex [24]3 years ago
6 0
Precipitation and runoff, Hope this helps!
tekilochka [14]3 years ago
6 0

precipitation water falls as rain

runoff.

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PLEASE HELP!!!!!!
lana66690 [7]

Answer:

the advances would be very good for the rate

Explanation:

Methods for reducing solid waste by reusing discarded materials. Recycling technologies use waste materials to make new products. They involve collecting recyclable materials, manufacturing or reprocessing them into new products, and purchasing products made from recycled materials

4 0
3 years ago
2. List three sources of error that could account for the differences between your values for the enthalpy of fusion of water an
Dvinal [7]

1 trial :  nothing is given for result comparision - so we have no idea if it's a mistake.

2nd trial : The results can be compared - if varies, one may go wrong, but which one?

3rd trial : If 3rd result is different from 1st and 2nd, it is unreliable.

calculating enthalpy of fusion. M, C and m,c = mass and specific heat of calorimeter and water, n, L = mass and heat of fusion of ice; T = temperature fall.

L = (mc+MC)T/n.

c=4.18 J/gK. assuming copper calorimeter , so C=0.385 J/gK.

1. M = 409g, m = 45g. T = 22c, n = 14g

L = (45*4.18+409*0.385)*22/14 = 543.0 J/g.

2. M = 409g, m = 49g, T = 20c, n = 13g

L = (49*4.18+409*0.385)*20/13 = 557.4 J/g.

3. M = 409g, m = 54g, T = 20c, n = 14g

L = (54*4.18+409*0.385)*20/14 = 547.4 J/g.

(i) Estimate error in L from spread of 3 results.

Average L = 549.3 J/g.

squared differences average (variance) = (6.236^2+8.095^2+1.859^2)/3 = 35.96

standard deviation = 5.9964

standard error = SD/(N-1) = 5.9964/2 = 3 J/g approx.

% error = 3/547 x 100% = 0.5%.

(ii) Estimate error in L from accuracy of measurements:

error in masses = +/-0.5g

error in T = +/-0.5c

For Trial 3

M = 409g, error = 0.5g

m = 463-409, error = sqrt(0.5^2+0.5^2) = 0.5*sqrt(2)

n =(516-463)-(448-409)=14, error = 0.5*sqrt(4) = 1.0g

K = (mc+MC)=383, error = sqrt[2*(0.5*4.18)^2+(0.5*0.385)^2] = 2.962

L = K*T/n

% errors are

K: 3/383 x 100% = 0.77

T: 0.5/20 x 100% = 2.5

n: 1.0/14 x 100% = 7.14

% errors in K and T are << error in n, so ignore them.

% error in L = same as in n = 7% x 547.4 = 40

The result is (i) L= 549 +/- 3 J/g or (ii) L = 550 +/- 40 J/g.

Both are very far above  334 J/g, so there is at least one systematic error  

e.g: calorimeter may not be copper, so C is not 0.385 J/gK. (If it was polystyrene, which absorbs/ transmits little heat, the effective value of C would be very low, reducing L.)

Using +/- 40 is best.

However, the spread in the actual results is much smaller

* measurements were "fiddled" to get better results; other Trials were made but only best 3 were chosen.

<h3>Other sources of error: </h3>

L=(mc+MC)T/n is too high, so n (ice melted) may be too small, or T (temp fall) too high - why?

* we have assumed initial and final temperature of ice was 0c, it may actually have been colder, so less ice would melt -which explain small values of n

* some water might have been left in container when unmelted ice was weighed (eg clinging to ice) - again this could explain small n;

* poor insulation - heat gained from surroundings, melting more ice, increasing n - but this would reduce measured L below 334 J/g not increase it.

* calorimeter still cold from last trial when next one started, not given time to reach same temperature as water - this would reduce n.

3 0
3 years ago
Water's high heat of vaporization allows it to cool us off when we sweat.<br> True<br> False
SCORPION-xisa [38]
False.

You’re body uses sweat to cool off in high temperatures. I don’t think vaporization has anything to go with it. Also, the water wouldn’t be hot since you’re cooling off by using it.
4 0
3 years ago
Which structures add to the fluidity of the plasma membrane:
Stels [109]

Answer:

(a) Carbohydrates are the structures  which add to the fluidity of the plasma membrane.

Explanation:

The principle components of plasma membrane are lipids, proteins and carbohydrates which are attached to some proteins and lipids. Membrane fluidity means how much viscous is the lipid bilayer of cell membrane? The membrane phospholipids absorbs fatty acids of different lengths and saturation. When there is amore distance between phospholipids fluidity increases.Another one is the  temperature and cholesterol. So these are the three factors which affects the fluidity of the membrane. The rate of saturated and unsaturated fatty acids decides the fluidity of the membrane at cold temperatures. Cholesterol take up the tasks as buffer blocking the lower temperatures from fluidity inhibition and blocking higher temperatures from increasing of fluidity.

6 0
3 years ago
The membrane structures that make up the cell are called
BlackZzzverrR [31]
B organelles
Like the mitochondria
7 0
3 years ago
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