Answer:
The expression is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CM%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B284%7D%26%7B483%7D%26%7B410%7D%5C%5C%7B597%7D%26%7B551%7D%26%7B233%7D%7B2%7D%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
From the question we are told that
The number of each items made in the month of January[J] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{144}&{474 }&{274}\\{598}&{572}&{302}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CJ%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B144%7D%26%7B474%20%7D%26%7B274%7D%5C%5C%7B598%7D%26%7B572%7D%26%7B302%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
The number of each items made in the month of February[F] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{ 424}&{492}&{546}\\{596 }&{530}&{164}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CJ%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%20424%7D%26%7B492%7D%26%7B546%7D%5C%5C%7B596%20%7D%26%7B530%7D%26%7B164%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Generally given that the production for March of all products at all locations was the average of the January and February production then the number of each items made in the month of March[M] is
![.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ \ \ \ \ \ \ \ C \ \ \ \ \ \ \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{\frac{144 +424}{2}}&{\frac{474 +492}{2}}&{\frac{274 +546}{2}}\\{\frac{598 +596}{2}}&{\frac{572 +530}{2}}&{\frac{302+164}{2}}\\\end{array}\right]](https://tex.z-dn.net/?f=.%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20B%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20T%5C%5CM%20%3D%20%5Cleft%20%5C%20%20NYC%7D%20%5Catop%20%7BLA%7D%7D%20%5Cright.%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%7B%5Cfrac%7B144%20%2B424%7D%7B2%7D%7D%26%7B%5Cfrac%7B474%20%2B492%7D%7B2%7D%7D%26%7B%5Cfrac%7B274%20%2B546%7D%7B2%7D%7D%5C%5C%7B%5Cfrac%7B598%20%2B596%7D%7B2%7D%7D%26%7B%5Cfrac%7B572%20%2B530%7D%7B2%7D%7D%26%7B%5Cfrac%7B302%2B164%7D%7B2%7D%7D%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=>
Answer:
<u>3.7</u>
Step-by-step explanation:
<u>Given</u>
- sin²θ + cos²θ = 1
- sinθ = 0.27
<u>Solving for cos</u>θ
- cos²θ = 1 - sin²θ
- cos²θ = 1 - (0.27)²
- cos²θ = 0.0729
<u>Finding tan</u>θ
- tanθ = sinθ / cosθ
- tanθ = 0.27 / 0.0729
- tanθ = <u>3.7</u>
<u>Verifying it lies in the range</u>
- θ = tan⁻¹ (3.7)
- θ = 74.88°
- Range is : 0 < θ < π/2 [or 0 < θ < 90°]
- It lies in the range [Verified]
Answer:
6/5
Step-by-step explanation:
hope this helps :)
Answer: 12.5 litres
Step-by-step explanation:
The SUV takes 2.5 litres for every 20 km driven.
The trip to work is 20 km which means that going to work costs Marie's father 2.5 litres every day in fuel.
In a week, there are 5 working days.
The amount of fuel used per week is therefore:
= 2.5 * 5
= 12.5 litres
