Question 1 (5 points) What is the solution to the system of equations? 3x +y = 4 2x + y = 5 (0, 4) Sof3 (-3, 12) (-3, 13) (-1,7)
1 answer:
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First, find the asymptotes.
When does f(x) become undefined? When the numerator is 0
0=4x-4
4=4x
x=1
Therefore, x cannot be 1, this is a horizontal asymptote.
We also know that when the degree of x in the numerator is smaller than the degree of x in the denominator, y=0.
Now that we have the horizontal asymptotes, find a third point to draw the graph.
If x=2,
f(2)=-3/4(2)-4
=-3/4
Be sure to include this points in your graph.
Hope I helped :)
When does f(x) become undefined? When the numerator is 0
0=4x-4
4=4x
x=1
Therefore, x cannot be 1, this is a horizontal asymptote.
We also know that when the degree of x in the numerator is smaller than the degree of x in the denominator, y=0.
Now that we have the horizontal asymptotes, find a third point to draw the graph.
If x=2,
f(2)=-3/4(2)-4
=-3/4
Be sure to include this points in your graph.
Hope I helped :)
