Tính thể tích V của khối chóp tứ giác đều S.ABCD có cạnh đáy bằng a, cạnh bên SA bằng 2a
1 answer:
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Answer:
The distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place)
Step-by-step explanation:
Given the points
- (3,4)
- (4,-6)
The distance 'd' between (3,4) and (4,-6)
substituting the points values
units (Rounded to the nearest the Tenths Place)
Thus, the distance is:
d = 10.0 units (Rounded to the nearest the Tenths Place)
Answer:
The average rate of change is -3.
Step-by-step explanation:
We are given the function:
And we want to find the average rate of change from <em>x </em>= 0 to <em>x </em>= 3.
In other words, we will compute the function at the two endpoints, and then find the slope of the line that crosses the two points.
For our first endpoint at <em>x</em> = 0, our function evaluates to:
So, our first point is (0, 9).
For our second endpoint at <em>x</em> = 3, our function evaluates to :
So, our second point is (3, 0).
Then by the slope formula, our average rate of change will be: