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solniwko [45]
3 years ago
15

PLEASE HELP!! I'VE DONE SO MANY TRIES BUT MY BRAIN ISN'T WORKING GEORGNERBH **WILL MARK BRAINLIEST + 50 POINTS**

Mathematics
2 answers:
mr_godi [17]3 years ago
8 0

0.07 - 2.69 = -2.62

X = -2.62

Explanation:

I’ve just done a lot of math

Hope this helps!

erica [24]3 years ago
6 0

Answer:

0.07 - 2.69 = x = -2.62

Step-by-step explanation:

x - -2.69 can be rewritten as x + 2.69

So, x + 2.69 = 0.07

Now subtract 2.69 from both sides to isolate x:

0.07 - 2.69 = x, so x = -2.62

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Is pi is more accurate than an answer that uses 3.14 for pi ?<br> .
Burka [1]

Answer: yes because pi = 22/7 as a fraction and as a decimal that never terminates

Step-by

6 0
3 years ago
PLEASEEEEE HELPPPPPP ASAPPPPPPPP
natta225 [31]

9514 1404 393

Answer:

  64r -48r -144

Step-by-step explanation:

The January cost expression is ...

  62p -48p -144 -432 = profit

The cost is identified as having 3 components, so the profit will have 4 components:

  (selling price)×p - ((cost per unit)×p +(fixed monthly cost)) -(first month startup cost) = profit

Comparing this to the given equation, we identify the components as ...

  selling price = 62

  cost per unit = 48

  fixed monthly cost = 144

  first month startup cost = 432

We note that 432 = 3×144, so is consistent with the description of startup costs.

Increasing the selling price by $2 will raise it from 62 to 64. In February, the initial month startup cost disappears, so the profit equation becomes ...

  (selling price)×r - ((cost per unit)×r +(fixed monthly cost)) = profit

  64r -48r -144 = profit

5 0
3 years ago
darryl spent $276 on books. math books cost $21 and English books cost $30. if he bought a total of 11 books how many of each ki
nata0808 [166]
6 math books would be 126
5 English books would be 150
126+150=276 
6 0
4 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
3 years ago
What division sentence means the same as the following subtract sentences?
Kaylis [27]
12 can be divisible by 8,4
8 0
3 years ago
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