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3 years ago

Expand 5(2x-4) please please

Mathematics

1 answer:

kotykmax [81]3 years ago

7 0

Answer:

10x - 20

Step-by-step explanation:

Distribute 5 to each of the terms within the parentheses to get 5(2x) - 5(4) = 10x - 20.

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A box is pulled to the right with a force of 65 N at an angle of 58 degrees to the horizontal. The surface is frictionless. The

lianna [129]

Answer:

34 N.

Step-by-step explanation:

Net force in x direction = 65 cos 58

= 34 N.

4 0

3 years ago

Read 2 more answers

Round 2,165.413 to the nearest hundredth.

stira [4]

2,200.413 is 2,165.413 to its nearest hundredth.

4 0

3 years ago

La respuesta de 5 da/

ArbitrLikvidat [17]

Creo que la respuesta de 5 da 5-5 porque realmente no hiciste una pregunta

3 0

3 years ago

You are interested in purchasing a new car. One of the many points you wish to consider is the resale value of the car after 5 y

lys-0071 [83]

Answer:

99% confidence interval for the true mean resale value of a 5-year-old car of this model is [$12,173.24 , $13,306.76].

Step-by-step explanation:

We are given that you manage to obtain data on 17 recently resold 5-year-old foreign sedans of the same model.

These 17 cars were resold at an average price of $ 12 comma 740 with a standard deviation of $ 800.

Firstly, the pivotal quantity for 99% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average price = $12,740

s = sample standard deviation = $800

n = sample of cars = 17

$\mu$ = true population mean

Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.921 < $t_1_6$ < 2.921) = 0.99 {As the critical value of t at 16 degree of

freedom are -2.921 & 2.921 with P = 0.5%}

P(-2.921 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.921) = 0.99

P( $-2.921 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.921 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X-2.921 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.921 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

99% confidence interval for $\mu$ = [ $\bar X-2.921 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.921 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,740-2.921 \times {\frac{800}{\sqrt{17} } }$ , $12,740+2.921 \times {\frac{800}{\sqrt{17} } }$ ]

= [$12,173.24 , $13,306.76]

Therefore, 99% confidence interval for the true mean resale value of a 5-year-old car of this model is [$12,173.24 , $13,306.76].

6 0

3 years ago

Which expession is equal to 2 −28 − − − − √ 2−28 ? 4 7i − − √ 47i 4i 7 √ 4i7 −4 7 √ −47 −4i 7 √

Strike441 [17]

Do problems 1-4, 11, 12 from appendix G in the book (page A47). ... Solution. 8 − 4i. (2.) (4 − 1. 2i) − (9 + 5. 2 i). Solution. −5 − 3i. (3.) (2 + 5i)(4 − i) ... Solution. 1, i, −1, and −i. 4. Write the product (. √3. 2. + 1. 2 i)(1. 2. +. √3. 2 ... (7.) 1+4i. 3+2i. Solution. 1+4i. 3+2i. = 1+4i. 3+2i · 3−2i. 3−2i. = 3−2i+12i−8i2 ..... i)8 = 28e8· 5π. 6.

7 0

3 years ago

Read 2 more answers