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Black_prince [1.1K]
2 years ago
6

When solved for c, the equation is c = k – 273.15 c = 273.15 – k c = k 273.15 c = 273.15k

Mathematics
1 answer:
charle [14.2K]2 years ago
8 0

The the equation K = C + 273.15 when solved for c is C = K - 273.15

<h3>Change of subject of formula</h3>

K = C + 273.15

  • subtract 273.15 from both sides

K - 273.15 = C

Therefore,

C = K - 273.15

Complete question:

The temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the equation K = C + 273.15.

Learn more about equation:

brainly.com/question/13763238

#SPJ1

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Can someone help me with these please.
ELEN [110]

Answer: Barbara did not include a variable in the term 1.49, which must represents the number of bottles of iced tea she needs to sell.

Step-by-step explanation:

Let be "x" the number of bottle of water Barbara needs to sell and "y"  the number of bottle of iced tea she needs to sell.

She sells iced tea for $1.49 per bottle and water for $1.25 per bottle, so she can write the following equation in order to calculate the number of bottles she needs to sell to earn $100:

1.25x + 1.49y = 100

Since Barbara wrote this equation:

1.25x + 1.49 = 100

We can conclude that the error Barbara made in writing the equation was: She did not include a variable in the term 1.49, which must represents the number of bottles of iced tea she needs to sell.

8 0
3 years ago
Nathan deposited 7/9 of his allowance into his savings account. He spent the remaining amount, or $2.50. How much did Nathan dep
inysia [295]
2/9=2.50
Allowence=2.50x9 divided by which gives you an answer of 11.25
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4 0
3 years ago
Consider the differential equation: y′′−8y′=7x+1. Find the general solution to the corresponding homogeneous equation. In your a
Margaret [11]

Answer:

yp = -x/8

Step-by-step explanation:

Given the differential equation: y′′−8y′=7x+1,

The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)

First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;

y′′−8y′=0

The auxiliary equation will give us;

m²-8m = 0

m(m-8) = 0

m = 0 and m-8 = 0

m1 = 0 and m2 = 8

Since the value of the roots are real and different, the complementary solution (yc) will give us

yc = Ae^m1x + Be^m2x

yc = Ae^0+Be^8x

yc = A+Be^8x

To get yp we will differentiate yc twice and substitute the answers into the original DE

yp = Ax+B (using the method of undetermined coefficients

y'p = A

y"p = 0

Substituting the differentials into the general DE to get the constants we have;

0-8A = 7x+1

Comparing coefficients

-8A = 1

A = -1/8

B = 0

yp = -1/8x+0

yp = -x/8 (particular integral)

y = yc+yp

y = A+Be^8x-x/8

3 0
3 years ago
M&lt;5=? what’s it equal
WINSTONCH [101]

Answer:

<8

Step-by-step explanation:

They are the same angle degree.

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How do write fifty and six hundredths in standard form
BaLLatris [955]
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