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xxTIMURxx [149]
3 years ago
11

Is it always best for a company to make decisions based on data, or are there some situations where they should not focus on dat

a?
Computers and Technology
1 answer:
Serhud [2]3 years ago
6 0

Answer:

data-driven decision

Explanation:

While 91% of companies say that data-driven decision-making is important to the growth of their business, only 57% of companies said that they base their business decisions on their data. Data-driven decision-making is a great way to gain a competitive advantage, increase profits and reduce costs!

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Which of the following is an example of a federal tax? A. Social Security tax B. Sales tax C. Property tax D. Transaction tax
Nastasia [14]
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6 0
3 years ago
Online Book Merchants offers premium customers 1 free book with every purchase of 5 or more books and offers 2 free books with e
andrey2020 [161]

Answer:

This question has two parts, first part is about programming about a Player class and second for reading string from user and decide how many time duck string entered by user and terminate if user press goose string.

The explanation of both program (executable code) is given below in explanation section.

Explanation:

//Program 1

#include <iostream>

using namespace std;

int main()

{

 bool isPremiumCustomer;

 int nbooksPurchased;

 int totalBookPurchasedWithOffer;

// bool cutomerType;

 int freeBooks;

 cout<<"Press 1 for Premium Customer and 0 for regular Customer";

 cin>>isPremiumCustomer;

 cout<<"How many books you purchased ";

 cin>>nbooksPurchased;

 

 

switch(isPremiumCustomer)// what type of customer is  

{

case 1://if customer is premium

 if (nbooksPurchased >= 5&&nbooksPurchased<8)// purchase book greater between 5 and 8

  {

   freeBooks=1;//offer free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

   

   cout<<"You purchased total book with offer ";//show total books

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 8)//if premium customer purchase more than 8 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;//total number of book including free book

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;//show total books

    }

  else{

   cout<<"You purchased total book with no offer ";

    cout<<nbooksPurchased;

   }

  break;

case 0:// if customer is regular customer

 if (nbooksPurchased >= 7&&nbooksPurchased<12)//and purchase book between 7 and 12

  {

   freeBooks=1;// offer 1 free book

   totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

   cout<<"You purchased total book with offer ";

   cout<<totalBookPurchasedWithOffer;

  }

   

  else if (nbooksPurchased >= 12)//if purchase 12 or more than 12 book

    {

    freeBooks=2;//offer two free book

    totalBookPurchasedWithOffer=nbooksPurchased+freeBooks;

    cout<<"You purchased total book with offer ";

    cout<<totalBookPurchasedWithOffer;

    }

 else{

  cout<<"You purchased total book with no offer ";

  cout<<nbooksPurchased;

  }

  break;

 

}

 

 

 

return 0;// terminate the program

 

}

/* program 1 has ended

and program 2 is started from here

#######################################################

*/

#include <iostream>

using namespace std;

int main()

{

string readstring;// take input string from user to enter either "goose" or "duck"

int count=0;//count the number of "duck"

while(readstring!="goose")//run loop, until user do not enter string  

{

 cout<<"Enter the string either goose or duck ";// prompt user to enter the string

 cin>> readstring;// read string from user

 if (readstring=="duck")//if string equal to "duck"

 {

  count=count+1;//count number of duck string enter by user

   

 }

}//exit/terminate the loop, if user enter the goose string

cout<< " Number of duck that were read " ;// show how many duck string entered by user

cout<<count;

return 0;// terminate the program

 

}

6 0
3 years ago
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