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IgorLugansk [536]
1 year ago
15

Determine if the given expression is written in simplestradical form.-V 150And why?

Mathematics
1 answer:
seropon [69]1 year ago
7 0
\text{Answer : -5}\sqrt[]{6}

Explanation

\begin{gathered} -\text{ }\sqrt[]{150} \\ \text{This can be express further by applying the laws of surd} \\ \sqrt[]{A\text{ x B}}\text{ = }\sqrt[]{A}\text{ x }\sqrt[]{B} \\ Step\text{ 1: Find the factor of 150 that will give one p}\operatorname{erf}ect\text{ square and non - p}\operatorname{erf}ect\text{ square} \\ Factor\text{ of 150 = 25 and 6} \\ \text{Threfore, }\sqrt[]{150}\text{ can be express as }\sqrt[]{25\text{ x 6}} \\ \sqrt[]{150\text{ }}\text{ = }\sqrt[]{25\text{ x 6}} \\ \sqrt[]{150\text{ }}\text{ = }\sqrt[]{25}\text{ x }\sqrt[]{6} \\ \sqrt[]{25}\text{ = 5} \\ -\sqrt[]{150}\text{ = -5}\sqrt[]{6} \\ \text{Therefore, the simplest form of -}\sqrt[]{150}\text{ is -5}\sqrt[]{6} \end{gathered}

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Step-by-step explanation:

When distributing a problem with 2 of the same signs, all you have to do is leave it the way it is. Basically pretend it's not there at all and you should the answer

4 0
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Write 3 other fractions that are equivalent to the given fraction. Include simplest Ford of the fraction
noname [10]

11.

\dfrac{16}{100} =\\1)=\dfrac{160}{1000} \\2)=\dfrac{32}{200} \\3)=\dfrac{4}{25}

12.

\dfrac{32}{48}=\\1) =\dfrac{4}{6} \\2)=\dfrac{64}{96} \\3)=\dfrac{2}{3}

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6 0
3 years ago
A tree DOUBLES in height each year until it reached its maximum height over the course of 10 years. How many years did it take f
RideAnS [48]

Answer:

9 years

the tree doubles in height

we can make a model

1 x 2 = 2

2 x 2 = 4

4 x 2 = 8

8 x 2 = 16

16 x 2 = 32

32 x 2 = 64

64 x 2 = 128

128 x 2 = 256

256 x 2 = 512

512 x 2 = 1024

Let's say 1024 is the maximum height

half the maximum height is 1024 x 0.5 = 512 so it will take 9 years because it reached 512 on the 9th year

Step-by-step explanation:

8 0
4 years ago
Which days are part of line BE?
d1i1m1o1n [39]

Answer:

B) Rays AB and AE

Step-by-step explanation:

Though A-F, A-D, and A-C all meet at one point on line B-E, point A, they aren't a <em>part</em> of it. Point A on line B-E marks the "midpoint" of it, and therefore, ray A-E and A-B are part of line B-E.

8 0
3 years ago
If MN=NQ and MQ=QR=RP, calculate for x​
Akimi4 [234]

Answer:

  • C. 18°

Step-by-step explanation:

  • <em>Refer to attached diagram</em>
<h3>Given </h3>
  • MN = NQ
  • MQ = QR = RP
  • NMR = 3x
  • QMR = x
<h3>To find</h3>
  • Value of x
<h3>Solution</h3>
  • MN = NQ  ⇒ ∠MRN = ∠QMN = 3x+x = 4x
  • MQ = QR ⇒ ∠MRQ = ∠QMR = x

<u>RQP is exterior angle of ΔMQR ⇒ </u>

  • ∠RQP = x + x = 2x

<u>QR = RP ⇒ </u>

  • ∠RPQ = ∠RQP = 2x

<u>∠QRN is exterior angle of ΔQRP ⇒ </u>

  • ∠QRN = 2x + 2x = 4x
  • ∠MRN = ∠QRN - ∠QRM = 4x - x = 3x

<u>∠MRN = ∠NMR = 3x ⇒ </u>

  • NR = MQ

<u>NR = MQ ⇒ </u>

  • ∠NQR = ∠QRN = 4x

<u>We now have a straight angle MQP:</u>

  • ∠MQP = ∠MQN + ∠RQN + ∠RQP
  • 180° = 4x + 4x + 2x
  • 10x = 180°
  • x = 18°

Correct choice is C

7 0
3 years ago
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