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IgorLugansk [536]
1 year ago
15

Determine if the given expression is written in simplestradical form.-V 150And why?

Mathematics
1 answer:
seropon [69]1 year ago
7 0
\text{Answer : -5}\sqrt[]{6}

Explanation

\begin{gathered} -\text{ }\sqrt[]{150} \\ \text{This can be express further by applying the laws of surd} \\ \sqrt[]{A\text{ x B}}\text{ = }\sqrt[]{A}\text{ x }\sqrt[]{B} \\ Step\text{ 1: Find the factor of 150 that will give one p}\operatorname{erf}ect\text{ square and non - p}\operatorname{erf}ect\text{ square} \\ Factor\text{ of 150 = 25 and 6} \\ \text{Threfore, }\sqrt[]{150}\text{ can be express as }\sqrt[]{25\text{ x 6}} \\ \sqrt[]{150\text{ }}\text{ = }\sqrt[]{25\text{ x 6}} \\ \sqrt[]{150\text{ }}\text{ = }\sqrt[]{25}\text{ x }\sqrt[]{6} \\ \sqrt[]{25}\text{ = 5} \\ -\sqrt[]{150}\text{ = -5}\sqrt[]{6} \\ \text{Therefore, the simplest form of -}\sqrt[]{150}\text{ is -5}\sqrt[]{6} \end{gathered}

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The sale bin in a clothing store contains an assortment of t-shirts in different sizes. There are 7 small, 8 medium, and 4 large
umka21 [38]

Answer:

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

Step-by-step explanation:

We have 7 small shirts, 8 medium shirts and 4 large shirts

Total number of shirts = 7 + 8 + 4 = 19 shirts

The probability that at least one of the first four shirts he checks is a large is given by

P(at least 1 large) = 1 - P(no large)

So first we need to find the probability that the none of the first four shirts he checks are large.

For the first check, there are 15 small and medium shirts and total 19 shirts so,

15/19

For the second check, there are 14 small and medium shirts and total 18 shirts left so,

14/18

For the third check, there are 13 small and medium shirts and total 17 shirts left so,

13/17

For the forth check, there are 12 small and medium shirts and total 16 shirts left so,

12/16

the probability of not finding the large shirt is,

P(no large) = 15/19*14/18*13/17*12/16

P(no large) = 0.352

Therefore, the probability of finding at least one large shirt is,

P(at least 1 large) = 1 - P(no large)

P(at least 1 large) = 1 - 0.352

P(at least 1 large) = 0.648

P(at least 1 large) = 64.8%

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3 years ago
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