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Aleksandr-060686 [28]
3 years ago
11

Solve S = 2πr2 + 2πrh for h

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
6 0

Answer:

h=2πr

Step-by-step explanation:

h=s-2πr^2;h=s-r^2;h=s-r:2πr

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Using an infinite geometric series for the repeating decimal 0.551¯¯¯¯¯¯¯¯, with ratio 11000, find integers a and b so that 0.55
irga5000 [103]

Answer:

Sum = 551/999

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Step-by-step explanation:

Given

Decimal = 0.551

Ratio = 1/1000

By repeating the decimal, we can write;

0.551 -bar = 0.551551551.....

0.551551551..... = 0.551 + 0.000551 + 0.000000551 + ....

= 551/1000 + 551/1000000 + 551/1000000000 + ......

= 551/10³ + 551/10^6 + 551/10^9 + .....

= n=0 Σ∝(551/10³)(1/10³)^n

Hence, the infinite geometrc series is Σ(551/10³)(1/10³)^n for n = 0 to

∝

Given the ratio of 1/1000

Let r = 1/1000

r = 1/10³

a = 551/10³

The sum is defined as follows;

a/(1-r)

Sum = 551/10³ / (1 - 1/10³)

Sum = 551/1000 ÷ 999/1000

Sum = 551/999

So, a/b = 551/999

Where a = 551 and b = 999

The two integers are 551 and 999

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If the sum of the measures of &lt;1 and &lt;2 is 180°, what is the sum of the measures of &lt;3 and &lt;4?
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D 180 degrees
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