Answer:
17
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
with reference angle 30°
perpendicular (p) = 5
hypotenuse (h) = x
Now
sin 30° = p / h
1 / 2 = 5 / x
x = 10
Hope it will help :)



<u>By first equation,</u>


<u>Now, we can find the original value of y.</u>








<u>Now, we can find the original value of x.</u>




Therefore, the values of x and y are 5 and 2 respectively.
I believe the answer is 0=1