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d1i1m1o1n [39]
2 years ago
13

Today, everything at a store is on sale. The store offers a 20% discount.

Mathematics
1 answer:
Mila [183]2 years ago
8 0
Answer: $14.40

10% of $18 = $1.80 (just divide it by 10)
$1.80 x 2 = $3.60
20% of $18 = $3.60

since it’s a discount, you subtract from the original price so:

$18 - $3.60 = $14.40
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A truck that can carry no more than 7100 lb is being used to transport refrigerators and upright pianos. Each refrigerator weigh
pishuonlain [190]

Let x be the number of refrigerators

Y be the number of pianos

So the inequality:

300x + 475y < 7100

So substitute 12 and 8 to the inequality

300(12) + 475(8) < 7100

3600 + 3800 < 7100

7400 < 7100 is not true

So it will overload the truck 

6 0
3 years ago
(8x – 20)-16 =10x+51
Lemur [1.5K]

When solving this equation, you get the answer as -43.5.

To solve, we simply need to collect like-terms and then rearrange to get x on one side and numbers on the other:

(8x - 20) - 16 = 10x + 51

8x - 36 = 10x + 51

- 8x

-36 = 2x + 51

- 51

-87 = 2x

÷ 2

-43.5 = x

I hope this helps!

6 0
3 years ago
I need help with finding 25 different numbers that add up to 51. It must be a six digit number. Example would be 6+7+5+8+9+6 = 4
USPshnik [31]
What you could do it is. Start adding numbers and once you get close to
6 numbers See if you are close to 51 and switch around the numbers to make it equal 51 hope this helps
6 0
3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 through 9, cannot be repeated. What is the probability that the loc
kozerog [31]
First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities
the second digit is any of the remaining 9, after having picked one. 
and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=\frac{n(first -digit- is- 5)}{n(all-codes)}= \frac{1*9*8*7 }{10*9*8*7 }= \frac{1}{10}=0.1

b. <span>What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6</span>
4 0
3 years ago
Read 2 more answers
Gente me ajudem prfvv em matemática
Tasya [4]

Answer:

Step-by-step explanation:

Trace a linha de 8cm, daí você vai dividir ela no meio, ou seja, no 4. Aí é só contar 2 cm para cada lado, que vai ser o 1, as pontas vão ser o 2. Tendeu? Daí é só marcar os pontos no -3/7(~-2,3), 1,6, 7/5(1,4), -1 e 0

6 0
2 years ago
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