The slope-intercept form:
m - slope
b - y-intercept → (0, b).
We have the points (4, 7) and (0, 7) → b = 7.
Calculate the slope:
Therefore we have 
The standard form: 
<h3>Answer: y = 7.</h3><h3><em>It's a horizontal line.</em></h3>
Answer:
(-1,-1) and (4.1).
1+1
slope of the line: m= ------- = 2/5
4+1
the slope of the perpendicular line: -5/2 and point (-1,3)
(y-3) = -5/2(x+1)
Answer:
y = -¼│x − 5│+ 3
Step-by-step explanation:
y = a│x − h│+ k
(h, k) is the vertex of the absolute value graph. In this case, it's (5, 3).
y = a│x − 5│+ 3
One point on the graph is (1, 2). Plug in to find the value of a.
2 = a│1 − 5│+ 3
2 = 4a + 3
a = -¼
Therefore, the graph is:
y = -¼│x − 5│+ 3
Answer:
9
Step-by-step explanation:
(15×4+3)/4 ÷(4×1+3)/4= 63/4 ÷ 7/4= 9
Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
