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2 years ago

PLEASE HELP IT IS DUE RIGHT NOW!!! WILL MARK BRAINLIEST!!!!!

Mathematics

1 answer:

pshichka [43]2 years ago

4 0

Answer:

(1,9)

Step-by-step explanation:

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I’m pretty sure the correct answer is A, but I’d like to double check

irinina [24]

3x² - 4 → A

(f + g)(x) = f(x) + g(x) = 2x² + 3 + x² - 7 = 3x² - 4

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4 years ago

PLEASE HELP ME !! GEOMETRY REFLECTIONS!! PLEASE EXPLAIN

mr_godi [17]

The reflected image 1 is the image of reflected in the mirror line y=0 and the reflected image under y =2 is reflected and the mirror line y is equal to 2 hence the answer is (5,2)...

the number that belongs to the green box is 5

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4 years ago

Please help me with this

Kisachek [45]

All you need to do is replace the variables with the numbers given.

t=9 & u=11

3+ 11t - 9u

3+ 11(9)-9(11)

3+ 99 - 99

The 99's cancel each other out, so you are left with 3.

The answer is 3.

7 0

3 years ago

Read 2 more answers

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

$(y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)$

Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$