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vekshin1
4 years ago
14

PLEASE HELP ME !! GEOMETRY REFLECTIONS!! PLEASE EXPLAIN

Mathematics
1 answer:
mr_godi [17]4 years ago
3 0
The reflected image 1 is the image of reflected in the mirror line y=0 and the reflected image under y =2 is reflected and the mirror line y is equal to 2 hence the answer is (5,2)...

the number that belongs to the green box is 5

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2x-3y=4<br> -4x+6y=-8. <br> solve by elimination
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4 years ago
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Find g(x), where g(x) is the translation 5 units right and 12 units up of f(x)=3x+5.
Rasek [7]
f(x)=3x+5\\\downarrow/5\ units\ right/\\f(x-5)=3(x-5)+5\\\downarrow/12\ units\ up/\\f(x-5)+12=3(x-5)+5+12\\\\g(x)=3(x-5)+17=3x-15+17=3x+2\\\\Answer:\ \boxed{g(x)=3x+2}


Look at the picture.

4 0
4 years ago
Jo had $5 more than Nate and together<br> they had $43. How much did Nate have?
Andru [333]

Answer:

Step-by-step explanation:

43-5

=$38

38/2=19

Nate has $19

hope this helps!

6 0
3 years ago
Read 2 more answers
A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when
Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

ME = Zc * σ \sqrt{n}

ME = 1.96 * 3 \sqrt{25}

ME = 1.18

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})

CI = (57.12 , 59.48)

b)

Given data:

mean, \bar X = 58.3

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

ME = zc * σ \sqrt{n}

ME = 1.96 * 3\sqrt{100}

ME = 0.59

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})

CI = (57.71 , 58.89)

c)

sample mean, \bar X = 58.3

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

ME = Zc * σ \sqrt{n}

ME = 2.58 * 3\sqrt{100}

ME = 0.77

CI = (\bar X - Zc * s\sqrt{n}  , \barX + Zc * s\sqrt{n})

CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

n \geq (zc *σ/E)^2

n = (2.58 * 3/0.5)^2

n = 239.63

7 0
4 years ago
Two number are
sweet-ann [11.9K]
Do you still need this
8 0
3 years ago
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