1/2=2/3x
x=3/4
please brainliest
hope this help
Given:
Uniform distribution of length of classes between 45.0 to 55.0 minutes.
To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:
45+55/2 = 50
So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
You plug -2 in for the function k(p) and add it to the function g(w), getting
(-2+3)*(-2-7)+(-2-5)^2=1*-9+49=40 for a - I challenge you to do B on your own!
Answer:
c = 4.79 feet
Step-by-step explanation:
Given question is incomplete without a picture; find the question with the attachment.
Two poles AD and DB of same length are leaning against each other.
Distance between the poles (AB) = 45 feet
m(∠ADB) = 180°- (60 + 50)°
= 70°
By sine rule,
= 36.68 ft
Similarly,
DB = 
= 41.47 ft
Now c = DB - AD
= 41.47 - 36.68
= 4.79 feet
<span>
The good answer is 9
(9:9=1 and 27:9=3)</span>
