See how many times the denominator goes into the numerator. For example, with 24/8, 8 goes into 24 three times, so 24/8 is 3. If I had 25/8, then it would be 3 1/8 because you have one left over after you divide the 8 into 25.
Answer:
Solution given:
For 1st
x²=71
For x=±
and
For 2nd
x³=71
For x=±![\sqrt[3]{71}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B71%7D)
So answer is:
In first row
<u>Solution to x²=71</u>
In second row
<u>Solution to </u><u>x³</u><u>=71</u>
In third row
<u>neither</u>
In forth row
<u>Solution to x³=71</u>
The absolute value of x is 4
Let the marks of Devi be x and Ali be y.
So, the equations:
2y = x <em>and</em> y + 16 = x
So,
2y = y + 16. [ because we know equals are equal to equals]
=> 2y - y = 16
=> y = 16
Check
Ali's marks are half of Devi's marks.
Devi's marks are 16 more than alis.
So, Devi's marks will be 16×2 = 32 and 32 is 16 greater than 16 (16+16=32).
