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3 years ago

Please help! I will give brainliest =D Please answer fast. I need help right now

Mathematics

2 answers:

hoa [83]3 years ago

5 0

Answer:

b or a

Step-by-step explanation:

makes more sense

sorry if wrong

Dafna11 [192]3 years ago

3 0

I’m pretty sure it’s a

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I need help with this please help me I need to show work too

crimeas [40]

Answer:

55+19.50m=250

Step-by-step explanation:

55 is the intial fee it doesn't have to be multiplied by anything.

19.50 is monthly it is multiplied by how many months she is going to be there. the amount of months is unknown so you use a variable I chose m for months or monthly.

it will be set equal to 250 because that is the amount of money that she has to spend.

I hope this helps I am sorry if it is wrong

6 0

3 years ago

A cell phone provider offers a plan that costs $40 per month plus $0.10 per text message sent or received. A comparable plan cos

anyanavicka [17]

It would be 300 text message for the plan to cost the same each month
Mark as brainly

7 0

3 years ago

Paco orders an ice cream for $1, but realizes his wallet is at home and he only has 3/20 of $1 with him. If his mom pays the rem

Svet_ta [14]

Answer: the answer is c) $0.85

Step-by-step explanation:

if he has 3/20 of a dollar that calculates to $0.15 and $1.00 minus $0.15 equals $0.85

3 0

3 years ago

Find dy/dx for y= x^3 ln (cot x)

ICE Princess25 [194]

<h3>Answer</h3>

$\dfrac{dy}{dx} = 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)$

<h3>Explanation</h3>

By the product rule $(d/dx)(f(x)g(x)) = f(x)g'(x) + g(x)f'(x)$ , we have

$\begin{aligned}\frac{dy}{dx} &= \left(x^3 \ln (\cot x) \right)' \\&= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \end{aligned}$

By the chain rule:

$\begin{aligned}\big(\ln (\cot x)\big)' &= \dfrac{1}{\cot x} \cdot (\cot x)' \\ &= \dfrac{1}{\cot x} \cdot -\csc^2 x\\&= -\tan (x) \csc^2(x) \\&= - \frac{\sin x}{\cos x} \cdot \frac{1}{\sin^2 x} = - \frac{1}{\cos x} \cdot \frac{1}{\sin x} \\&= -\csc(x)\sec(x)\end{aligned}$

By the power rule:

$(x^3)' = 3x^2$

thus

$\begin{aligned}\frac{dy}{dx} &= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \\&= x^3\big( -\csc(x)\sec(x) \big) + \ln(\cot x) \cdot (3x^2) \\&= -x^3 \csc(x)\sec(x) + 3x^2 \ln(\cot x) \\&= 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)\end{aligned}$

Nothing to do to simplify any further, other than factoring out $x^2$ .

4 0

3 years ago

What is 96 fluid ounces equal to in quarts? You will get a thank if answered!

muminat

Hey, should be 3 american quarts

4 0

3 years ago

Read 2 more answers