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damaskus [11]
2 years ago
9

Whose procedure is correct? keisha’s procedure is correct. david’s procedure is correct. both procedures are correct. neither pr

ocedure is correct.
Mathematics
1 answer:
8_murik_8 [283]2 years ago
6 0

Both procedures are correct. Because the end answer and the step-by-step explanation are right.

<h3>What is the procedure?</h3>

It is a step-by-step explanation of the equations. The procedure is important

It explains the sequence of actions and specifies what has to be done at each stage, frequently specifying when and by whom the procedure should be conducted.

The end answer for Keisha's solution is;

\rm cos \theta =± \frac{15}{17}

The end answer for David's solution is;

\rm cos \theta =± \frac{15}{17}

Hence both procedures are correct. Because the end answer and the step-by-step explanation are right.

To learn more about the procedure refer to the link;

brainly.com/question/14553685

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1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Solve the compound inequality 6b &lt; 36 or 2b + 12 &gt; 6.
ss7ja [257]

Answer:

all values of b

Step-by-step explanation:

6b < 36 or 2b + 12 > 6.

First solve the one on the left

6b < 36

Divide by 6

6b/6 < 36/6

b  <6

Then solve the one on the right

2b + 12 > 6

Subtract 12 from each side

2b+12-12 >6-12

2b >-6

Divide by 2

2b/2 >-6/2

b >-3

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Rewriting

b>-3  or b<6

b > -3 is an open circle at -3 with a line going to the right

b < 6 is an open circle at 6 with a line going to the left

The or means we add the lines together

We have a line going from negative infinity to infinity

all values of b

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Answer:

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