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liberstina [14]
2 years ago
11

Elisa bought some boxes of pencils for $3.99 each and some boxes of pens at $4.99 each. If p represents the number of boxes of p

encils and b represents the number of boxes of pens, which equation describes the relationship between these two variables if she spent a total of $39.91 on these items?
A. 4.99p + 3.99b = 39.91
B. 4.99p - 3.99b = 39.91
C. 3.99p + 4.99b = 39.91
D. 3.99p - 4.99b = 39.91
Mathematics
1 answer:
vladimir2022 [97]2 years ago
8 0

The equation which describes the relationship between these two variables is 39.91 = 3.99p + 4.99b

Given:

<em>Cost of each box of pencil</em> = $3.99

<em>Cost of each box of pen </em>= $4.99

<em>Total cost</em> = $39.91

let

p = <em>number of boxes of pencils</em>

b = <em>number of boxes of pens</em>

The equation:

<em>Total cost = (Cost of each box of pencil × number of boxes of pencils) + (Cost of each box of pen × number of boxes of pens)</em>

39.91 = (3.99 × p) + (4.99 × b)

39.91 = 3.99p + 4.99b

Therefore, equation which describes the relationship between these two variables is 39.91 = 3.99p + 4.99b

Read more:

brainly.com/question/8957185

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<span>1. The r</span>atio of milk cartons taken to total milk cartons,
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73/100 is the ratio of milk cartons taken to total milk cartons

2. The ratio of milk cartons remaining to milk cartons taken
27 / 73 is the ratio of milk cartons remaining to milk cartons taken
7 0
3 years ago
Angles 1 and 2 are supplementary. 2 lines intersect to form angles 1 and 2. Which equation represents the relationship between t
mamaluj [8]

Answer:

\angle 1 + \angle 2 = 180^o

Step-by-step explanation:

Given

\angle 1 and \angle 2

Required

The relationship between them \angle 1 and \angle 2

From the question, we understand that \angle 1 and \angle 2 are supplementary

Supplementary angles add up to 180.

So, the relationship between \angle 1 and \angle 2 is:

\angle 1 + \angle 2 = 180^o

7 0
2 years ago
The figure below shows a rectangle ABCD having diagonals AC and DB: A rectangle ABCD is shown with diagonals AC and BD. Jimmy wr
yaroslaw [1]

Answer:

C. DC = DC. By reflexive property of equality.

Step-by-step explanation:

We are given that,

In step 4, Jimmy proved ΔADC ≅ ΔBCD by the SAS Congruence Postulate.

For that, the previous steps states,

Step 1: AD = BC, as opposite sides of a rectangle are congruent.

Step 2: ∠ADC = ∠BCD

So, in order to satisfy the SAS Postulate, we must have another pair of sides equal from the respective rectangles.

As, we can see that in ΔADC and ΔBCD, the side DC is a common side.

Thus, in the missing step, we get,

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5 0
2 years ago
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NEED HELP FAST 15 POINTS
Flauer [41]

Answer:Can somebody please help

Step-by-step explanation:

6 0
3 years ago
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What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?
Maksim231197 [3]
Hello,
 the first step should be to distribue:
-4(3-5x)= -12+20x

Teh resolution may be:

-4(3-5x)>=-6x+9
==>-12+20x>=-6x+9
==>20x+6x>=9+12
==>26x>21
==>x>=21/26

But an other way may be used:

-4(3-5x)>=-6x+9
==>3-5x<= -6x/(-4)+9/(-4)
==>-5x-3/2 x<=-9/4 -3

==>-13/2 x <=-21/4

==>x>= -21/4 *(-2/13)
==>x>=21/(2*13)
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5 0
3 years ago
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