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Serggg [28]
2 years ago
15

Area of octagon with radius 5?

Mathematics
1 answer:
Montano1993 [528]2 years ago
3 0
I got 200 from a octagon with the diameter of 10
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A point (x,y) in the xy-plane whose coordinates satisfy xy<0 lies in quadrant(s) ____ or ____ .
lubasha [3.4K]
The possible ordered pairs whose product will be negative (less than zero) are,


(x,-y)  \: or \:  (-x,y)

That is all these products will give us,

- xy

-xy< 0

The point must be in the second quadrant where x is negative and y is positive.


Or in the fourth quadrant, where y is negative and x is positive.

5 0
3 years ago
8. Find the area of each figure to the nearest tenth.<br><br> Please Help!
Cloud [144]
Hopefully this helps

is it ten or tenth?

If it's ten,

88 = 90
18550 = 18550

Tenth

18550 = 18550.0
88=88.0

3 0
3 years ago
Which contract costs more per month? An 18 month cable contract for $2070 or a 12 month contract at $1776? Which is the better d
Dafna1 [17]

Answer:

Contract A is cheaper because $115 per month is less than $148 per month

Step-by-step explanation:

To find the unit price we divide the total cost given by the total months given for each contract to find out the cost per month.

$2070/18 months = $115 per month

$1776/12 months = $148 per month

Contract A is cheaper because $115 per month is less than $148 per month

7 0
3 years ago
How to solve these question?
mart [117]
3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the  graph is 0 because the line tangent to the point is horizontal. We can find the rate of change  by taking the derivative of the function.

y' = 2ax + b

Now that we where the derivative, we can set it equal to 0.

2ax + b = 0

We also know that at the extreme value, x = -1/2. We can plug that in as well.

2a (-\frac{1}{2} ) + b = 0

The 2 and one-half cancel each other out.

-a + b = 0

a = b

Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.

a(-0.5)^2 + a(-0.5) + 10 = 0

0.25a - 0.5a + 10 = 0

-0.25a = -10

a = 40

b = 40

To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.

80x + 40

Our critical number is x = -1/2. We need to plug a number that is less than -1/2  and a number that is greater than -1/2 into the derivative.

LESS THAN:
80(-1) + 40 =  -40

GREATER THAN:
80(0) + 40 = 40

The rate of change of the graph changes from negative  to positive at x = -1/2, therefore the extreme value is a minimum.

4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.

y' = 2ax + 1

2a(3) + 1 = 0

6a = -1

a = -1/6

So now plug the a value and x=3 into the original function to find the extreme value.

(-1/6)(3)^2 + 3 + 3 = 4.5

The extreme value is 4.5


7 0
3 years ago
Write an expression to represent the quotient
Monica [59]
Quotient=(dividend-remainder)/divisor
8 0
3 years ago
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