Answer:
Place the compass at S and adjust its width to point P.
Step-by-step explanation:
Here are the remaining steps to complete the construction.
The next step for Alice is to place the compass at point S and adjust its width to point P.
Next step is, without changing the width, place the compass at point T, draw another arc and cut the previously drawn arc. Label the new point as U.
Now, using straightedge, join points R and U.
RU is the required line that passes through R and parallel to LQ.
2x^2-4x-30 would be your answer
<span><span>(<span><span>2x</span>−10</span>)</span><span>(<span>x+3</span>)
</span></span><span>=<span><span>(<span><span>2x</span>+<span>−10</span></span>)</span><span>(<span>x+3</span>)
</span></span></span><span>=<span><span><span><span><span>(<span>2x</span>)</span><span>(x)</span></span>+<span><span>(<span>2x</span>)</span><span>(3)</span></span></span>+<span><span>(<span>−10</span>)</span><span>(x)</span></span></span>+<span><span>(<span>−10</span>)</span><span>(3)
</span></span></span></span><span>=<span><span><span><span>2<span>x2</span></span>+<span>6x</span></span>−<span>10x</span></span>−30
</span></span><span>=<span><span><span>2<span>x2</span></span>−<span>4x</span></span>−<span>30</span></span></span>
You follow bedmas (brackets, exponents,division,multiplication,addition,subtraction). First comes the brackets so you do (60 divided by 10) which is 6. You still have (6) which means you have to multiply it by 2. So you get 12. Now you got rid of the brackets so you can solve the rest. 90-12-4= 74.
Answer:
Option B) 0.2143
Step-by-step explanation:
We are given the following in the question:
Numbers of exposures(x): 4,3,7
We have to find the maximum likelihood estimate of p.
Formula:
Putting the values, we get,
Thus, the correct answer is
Option B) 0.2143
Answer:
Step-by-step explanation:
We have been given that an arrow is shot straight up from a cliff 58.8 meters above the ground with an initial velocity of 49 meters per second. Let up be the positive direction. Because gravity is the force pulling the arrow down, the initial acceleration of the arrow is −9.8 meters per second squared.
We know that equation of an object's height t seconds after the launch is in form 
, where
g = Force of gravity,
= Initial velocity,
= Initial height.
For our given scenario 
, 
and 
. Upon substituting these values in object's height function, we will get:
Therefore, the function for the height of the arrow would be .
