A relation is a function if _____.

Mathematics

1 answer:

valentina_108 [34]3 years ago

8 0

... exactly one output for each input

This is an important concept; be certain that you understand it.

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a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o

marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

Find the gross area of the garden.

Square 150m = 22,500 sqm.

Step 2:

Find the area of the pool.

Square 25m = 625 sqm.

Step 3:

Subtract the area of the pool from the gross area of the garden

to find the net area of the garden.

22,500 - 625 = 21,875 sqm.

Warning:

Do not subtract the side length of the swimming pool from the side length

of the garden before squaring.

7 0

3 years ago

15) Solve for X X\42=6 A) 7 B) 252 C) 260 D) 332

Vikentia [17]

Answer:

b)252 is the answer

Step-by-step explanation:

x\42=6

x=6*42

x=252

5 0

2 years ago

Can someone help me out

LiRa [457]

3/196

Step-by-step explanation:

multiply everything

5 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$