Solve the linear equation 2. 25 – 11j – 7. 75 + 1. 5j = 0. 5j – 1. J = –0. 45 j = –0. 25 j = 0. 25 j = 0. 45.
1 answer:
You might be interested in
The image that has the 10N forward force alone is the fastest while the image that has the 10N forward force and two 5N backward forces is the slowest.
<h3>What is acceleration?</h3>The term acceleration refers to the change of velocity with time. The acceleration of a body depends on the mass of the body and the force acting on it.
Looking at the image attached, the image that has the 10N forward force alone is the fastest while the image that has the 10N forward force and two 5N backward forces is the slowest.
Learn more about acceleration: brainly.com/question/12134554
The Angle HCA is equal to 52°. This is arrived at using the knowledge of the Total value of Angles in a Triangle and the Total Value of Angles in a Polygon.
<h3>What other principles were used to arrive at the answer?</h3>
The other principles of mathematics that were used to arrive at the above answer are:
- Total Angles on a straight line;
- Total Angles on a point; and
- Line segments.
Step 1 - Recall that we have been given Angles AHB and BAH to be 128° and 28° respectively.
We also know that:
- The sum of angles in a triangle is 180°;...................A
- The sum of angles on a straight line is 180°;.........B
- The sum of angles in a polygon is 360°; while.....C
- The total sum of angles at a point is 360°.............D
Since A...therefore:
When ∠AHB (128°) and ∠BAH are taken from 180° we have DBA = ∠28°.
By observation, we can deduce that ∠BDE, ∠CDH, ∠CEH and ∠AEH are all right-angled triangles.
Using the above, we are able to repeat this process of solving for each angle until we have ∠HCA.
To verify that our answer is correct, recall that sum of angles in a polygon is 360°
That means:
∠BDA + ∠DHE + ∠CEH + ∠HCA = 360°
That is, 90+ 128 + 90 + 52 = 360°
See attached images and;
Learn more about Angles in a Triangle at:
brainly.com/question/25215131
#SPJ1
