The system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.
<h3>How to solve Algebra Word Problems?</h3>
Let the first number be x and the second number be y.
We are told that three times the square of a number is greater than a second number. Thus; 3x² > y
Now, The square of the second number increased by 6 is greater than the first number. Thus;
y² + 6 > x
Thus, the system of inequalities that represents the given criteria are 3x² > y and y² + 6 > x.
where;
x is first number and y is second number.
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X=3 and y=-8
I solved using substitution, but you can also use elimination. x = 2y+19, find x, then find y.
Answer:
I would be disappointed in myself and probably think I am stupid.
Hope this helps/ have a great day/night!
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<em>brainly.com/question/11815303</em>
We have
x = t³ ===> dx/dt = 3t²
y = t⁴ ===> dy/dt = 4t³
Then with the given parameteriztion, the line integral along C of x/y is








