N+(n+1)+(n+2)+(n+3)+(n+4)+(n+5)=270
We use these terms to represent the first six consecutive integers in the sequence
Now we group like terms:
6n+15=270
Minus 15 from both sides of the equation
6n=255
n=42.5 which is not an integer
Is this a joke question?
Besides that, the 2nd number will be 43.5
Answer:
288 will be ur ans
Step-by-step explanation:
1440 x 80/100
=1152
1440-1152
=288
3
2
+
3
−
7
Distribute
(
6
2
−
4
−
5
)
−
1
(
3
2
−
7
+
2
)
(
6
x
2
−
4
x
−
5
)
−
1
(
3
x
2
−
7
x
+
2
)
(6x2−4x−5)−1(3x2−7x+2)
(
6
2
−
4
−
5
)
−
3
2
+
7
−
2
The answer is (3x - 4) (x + 3)
Answer:
0.54545454545
Step-by-step explanation:
3/11*2
