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aleksley [76]
4 years ago
6

The space shuttle is accelerated off its launch pad to a velocity of 525 m/s in 18.0 seconds.

Mathematics
1 answer:
deff fn [24]4 years ago
6 0

Answer:

<h2> 29.17m/s²</h2>

Step-by-step explanation:

Acceleration is defined as the change in velocity of a body with respect to time.

Acceleration = velocity/time

Given velocity of the space shuttle = 525m/s and time = 18.0seconds

Its average acceleration = 525/18

Its average acceleration (in m/s²) = 29.17m/s²

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faltersainse [42]
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3 years ago
F(x)= x-2/ x-4
hodyreva [135]

Answer:

The discontinuity is x = 4

There no holes

The equation of the vertical asymptote is x = 4

The x intercept is 2

The equation of the horizontal asymptote is y = 1

Step-by-step explanation:

* Lets explain the problem

∵ f(x)=\frac{x-2}{x-4}

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∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

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* The discontinuity is x = 4

- A hole occurs when a number is both a zero of the numerator

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∵ The numerator is x - 2

∵ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

∵ The denominator is x - 4

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

∵ There is no common number makes the numerator and denominator

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∴ There no holes

- Vertical asymptotes are vertical lines which correspond to the zeroes  

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- x- intercept is the values of x which make f(x) = 0, means the

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∵ f(x) = 0

∴ \frac{x-2}{x-4}=0 ⇒ by using cross multiplication

∴ x - 2 = 0 ⇒ add 2 to both sides

∴ x = 2

* The x intercept is 2

- If the highest power of the numerator = the highest power of the

 denominator, then the equation of the horizontal asymptote is

 y = The leading coeff. of numerator/leading coeff. of denominator

∵ The numerator is x - 2

∵ The denominator is x - 4

∵ The leading coefficient of the numerator is 1

∵ The leading coefficient of the denominator is 1

∴ y = 1/1 = 1

* The equation of the horizontal asymptote is y = 1

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3 years ago
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3 years ago
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Help pls! Idk what to do with this one.
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Approximately what portion of the circle is shaded blue?<br><br> A. 2/3<br> B. 2/10 C.2/5
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