Answer:
(6,35)
Step-by-step explanation:
Set both equations equal to each other and solve for x
8x+11=5x+29, Subtract 5x from both sides
3x+11=29, Subtract 11 from both sides
3x=18 Divide by 3
x=6
Substitute x=6 back into either equation to solve for y
y=8(6)+11
y=48+11
y=59
Answer: it is x=5/7 or x=-5/7
Answer:
(f - g)(x) = x² - 3x - 70
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 2x - 63
g(x) = x + 7
(f - g)(x) is f(x) - g(x)
<u>Step 2: Find (f - g)(x)</u>
- Substitute: (f - g)(x) = x² - 2x - 63 - (x + 7)
- Distribute -1: (f - g)(x) = x² - 2x - 63 - x - 7
- Combine like terms (x): (f - g)(x) = x² - 3x - 63 - 7
- Combine like terms (Z): (f - g)(x) = x² - 3x - 70
Answer:

Step-by-step explanation:
Given
Quadratic equation is

Roots of the quadratic equation
are

So, for the given equation roots are
