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m_a_m_a [10]
3 years ago
7

I don’t understand how to do these and this assignment is due today :((

Mathematics
1 answer:
salantis [7]3 years ago
8 0

Answer:

Step-by-step explanation:

8 , 12 , 16 , 20  .......

First term = a = 8

Common difference = second term - first term = 12 - 8= 4

nth term = a + (n-1) * d

               = 8 + (n -1) * 4

                = 8 + 4n - 4

                 = 4n + 8 - 4

                 = 4n + 4

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Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

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\bar X represent the sample mean for the sample  

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\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

2) Solution to the problem

Since the new Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Assuming that the deviation is known we can express the margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =\pm 3 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.64(14.7)}{3})^2 =64.57 \approx 65

So the answer for this case would be n=65 rounded up to the nearest integer

And the sample size would decrease by 160-65=95 subjects

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